Energy Transfer (OCR AS Physics): Revision Note

Exam code: H156

Ashika

Written by: Ashika

Reviewed by: Caroline Carroll

Updated on

Energy Transfer in Circuits

  • E.m.f is defined as the energy transferred by the power supply per unit charge

  • This energy transformed is also equal to the work done by the moving charge

  • This is defined by the equation:

W = εQ

  • Where:

    • W = work done / energy transferred (J)

    • ε = e.m.f (V)

    • Q = charge (C)

  • The potential difference is the energy transferred to the electrical component per unit charge

  • This means the equation can also be written as:

W = VQ

  • Where:

    • V = potential difference (V)

  • These equations show that

1 V = 1 J C-1

Worked Example

An electric kettle requires 0.4 MJ to be supplied to boil a cup of water. The e.m.f. of the mains supply is 230 V.Calculate the charge supplied.

Answer:

Step 1: List the known quantities

  • Energy transferred (work done), W = 0.4 MJ = 0.4 × 106 J

    • E.m.f, ε = 230 V

Step 2: Write the relevant equation

W = εQ

Step 3: Rearrange for charge, Q

Q = W ÷ ε

Step 4: Substitute in the values

Q = (0.4 × 106) ÷ 230 = 1739.13 = 1700 C

Energy Transfer for Charged Particles

  • A dynamo or battery transfer energy to each charge carrier, which are electrons in metals, as they pass through

    • Each electron has a charge of e

  • Since the energy transferred (work done) W is defined as

W = QV

  • Then:

W = eV

  • Where the charge Q is now replaced with the charge of the electron e

  • 1 eV is 1 electronvolt, which is defined as:

    A unit of energy equal to the work done by an electron accelerated through a potential difference of 1 volt

  • When a potential difference is applied across a conductor, the electrons are accelerated and gain kinetic energy

 

Electronvolt, downloadable AS & A Level Physics revision notes

Electron beam accelerated through a potential difference of 1 V

  • This kinetic energy gained is equal to an electronvolt:

eV = ½ mv2

  • Where:

    • e = elementary charge (C)

    • V = potential difference (V)

    • m = mass of the electron (kg)

    • v = speed of the electrons (m s-1)

  • To convert between eV and J:

    • eV → J: multiply by 1.6 × 10-19

    • J → eV: divide by 1.6 × 10-19

Worked Example

Calculate the speed of an electron that is accelerated through a potential difference of 5 V.

Answer:

Examiner Tips and Tricks

Remember to clearly state the difference between lower case v meaning velocity and upper case V meaning the potential difference in your exam, otherwise, you may define or substitute the wrong value!

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Build on this topic

Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.