Power (OCR AS Physics): Revision Note

Exam code: H156

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

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Power

  • Power is defined as:

The rate of energy transfer

  • Since work done is equal to the energy transferred, power can also be defined as:

Work done per unit time

  • Power can be calculated using the following equations:

P = Et = Wt

  • Where:

    • P = power in watts (W)

    • E = energy in joules (J)

    • W = work done in joules (J) or newton metres (N m)

    • t = time in seconds (s)

  • Power is also used in electricity, with labels on lightbulbs which indicate their power, such as 60 W or 100 W

    • These indicate the amount of energy transferred by an electrical current rather than by a force doing work

The Watt

  • The watt (W) is the unit for power (and radiant flux)

    • It is defined as 1 W = 1 J s-1

  • In SI base units, the watt is kg m2 s–3

  • One watt is defined as:

A transfer of energy of 1 J in 1 s

Worked Example

A car engine exerts the following force for 1.0 km in 200 s.

A car with a forward force of 500 N acting on it, travelling a distance of 1.0 km.

What is the average power developed by the engine?

Answer: 

Step 1: List the known quantities and convert to SI units

  • Force, F = 500 N

  • Displacement, s = 1.0×103 m

  • Time, t = 200 s

Step 2: Substitute the work done equation into the power equation

P = Wt

W = Fs

P = Fst

Step 3: Substitute the known values to calculate

P = 500 × (1.0×103)200

P = 2500 W

Examiner Tips and Tricks

Think of power as “energy per second”. Thinking of it this way will help you to remember the relationship between power and energy: “Watt is the unit of power?”

Power & Force

  • If an object is moving at constant velocity with a constant force, the power can be calculated by:

P = Fv

  • Where:

    • F = force (N)

    • v = velocity (m s–1)

  • This equation is only relevant where a constant force moves a body at constant velocity

  • Power is required in order to produce an acceleration

  • The force must be in the direction of the velocity

    • Otherwise, the component of the force in the direction of the velocity must be used instead

Derivation of P = Fv

  • Power is the rate of doing work

P = Wt

  • Work is done when a force moves an object over a distance

W = Fs

  • At a constant velocity, the distance moved by the object can be described as:

d = vt

  • Substituting this into the work done equation gives:

W = Fvt

  • And substituting this into the power equation gives:

P = Fvtt

P = Fv

Worked Example

A lorry moves up a road that is inclined at 14.5° to the horizontal.

A lorry travelling at 9.4 m s⁻¹ up a straight road inclined at 14.5° to the horizontal.

The lorry has a mass of 3500 kg and is travelling at a constant speed of 9.4 m s-1. The force due to air resistance is negligible.

Calculate the useful power from the engine to move the lorry up the road.

Answer:

Step 1: List the known quantities

  • Mass, m = 3500 kg

  • Speed, v = 9.4 m s-1

  • Angle of incline = 14.5°

Step 2: State the equation for power in motion

P = Fv

Step 3: Calculate the component of the applied force which overcomes the weight

5-1-5-worked-example-p-fv-2-cie-new

F = mgsinθ

F = 3500 × 9.81 × sin(14.5)

F = 8596.8 N

Step 4: Substitute the known values into the power equation to calculate

P = 8596.8 × 9.4

P = 81 000 W (2 s.f.)

Examiner Tips and Tricks

The force represented in exam questions will often be a drag force. Whilst this is in the opposite direction to its velocity, remember the force needed to calculate the power is equal to (or above) this drag force to overcome it, therefore, you equate it to that value.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.