Concavity of Functions (College Board AP® Calculus AB): Revision Note

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Updated on

Concavity of functions

What is concavity?

  • Concavity is the way in which a curve bends and is related to the second derivative of a function

  • A curve is:

    • Concave up if f'(x) is increasing in this interval

      •  f''(x)0 for all values of x in an interval

    • Concave down if f'(x) is decreasing in this interval

      •  f''(x)0 for all values of x in an interval

Diagram comparing concave up (left) and concave down (right) curves, highlighting tangent lines.
Example of how tangents change based on the concavity of the curve

Examiner Tips and Tricks

Zero is included in both the inequalities above because the function could be concave up or concave down when  f''(x)=0. However, in your exam, you will only need to use  f''(x)>0 or  f''(x)<0 to find the concavity of functions. The functions will be chosen to make this work.

How do I find where a function is concave up or concave down using the second derivative?

  • The second derivative of a function, f''(x), describes the rate of change of the first derivative, f'(x)

    • If the rate of change is positive, the first derivative is increasing

    • If the rate of change is negative, the first derivative is decreasing

  • This means you can determine if a function is concave up or down at a point using the second derivative

    • If f''(a)>0 then f is concave up at x=a

    • If f''(a)<0 then f is concave down at x=a

  • You can also find an interval where a function is concave up or down

    • To find where the function is concave up,

      • Solve the inequality f''(x)>0

    • To find where the function is concave down,

      • Solve the inequality f''(x)<0

What happens if the second derivative is zero?

  • If f''(a)=0 then the function could be concave up, concave down, or neither at these points

  • You determine what is happening at this point by looking at the sign of the second derivative on either side of this point

    • If the second derivative is positive on either side of the point, then f is concave up at x=a

      • Consider f(x)=x4

      • f''(0)=0

      • f''(0.01)>0 and f''(0.01)>0

      • Therefore, f is concave up at (0, 0)

    • If the second derivative is negative on either side of the point, then f is concave down at x=a

      • Consider f(x)=x4

      • f''(0)=0

      • f''(0.01)<0 and f''(0.01)<0

      • Therefore, f is concave down at (0, 0)

    • If the sign of the second derivative changes on either side of the point, then f is neither concave up nor concave down

      • Consider f(x)=x3

      • f''(0)=0

      • f''(0.01)<0 and f''(0.01)>0

      • Therefore, f is neither concave up nor concave down at (0, 0)

      • It is called a point of inflection

How do I find points of inflection?

  • Find the points where the second derivative is zero

    • The value of the first derivative could be any value

  • Find the sign of the second derivative around the points to find whether the concavity changes

    • Check whether it goes from concave up to concave down or vice versa

    • If it does, then the point is a point of inflection

Graph of y = f(x) with concave down red sections, concave up green sections, and two blue points of inflection where fʺ(x) changes sign and equals zero
Examples of points of inflection

Examiner Tips and Tricks

In an exam, an easy way to remember the difference is:

  • Concave down is the shape of (the mouth of) a sad smiley ☹️

    • They are feeling negative!

  • Concave up is the shape of (the mouth of) a happy smiley 🙂

    • They are feeling positive!

Worked Example

The function f is defined by

f(x)=sinx,   0x2π

State the open interval for which f is concave down.

Answer:

A function is concave down when f''(x) is negative

f'(x)=cosxf''(x)=sinx

The following must then be solved in the given domain

sinx < 0,   0x2π

The easiest way to solve this is with a graph of y=sinx

Sketch the graph of y=sinx for 0x2π and highlight where the graph is less than zero

Graph of -sinx with 0 to pi highlighted (where it is below the x-axis)

The function is concave down on the interval where the second derivative is less than or equal to zero,

Concave down when 0<x<π

Concave down on (0, π) because  f''(x)<0

Worked Example

Let the function f be defined by f(x)=x33x2+3.

Find the coordinates of the point of inflection on the graph of y=f(x). Justify how you know it is a point of inflection.

Answer:

Points of inflection have a second derivative of zero

Potential points of inflection can therefore be found by setting f''(x)=0

f''(x)=6x6

6x6=0x=1

Find the y-coordinate

f(1)=1

(1, 1)

So the point at (1, 1) could be a point of inflection

Check the sign of the second derivative at either side of x=1 to find the concavity of the curve

f''(0.9)=0.6

f''(1.1)=0.6

Just before x=1,  f is concave down because  f''(x)<0

Just after x=1,  f is concave up because  f''(x)>0

Therefore,  f has a point of inflection at (1, 1) because the concavity changes

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Jamie Wood

Author: Jamie Wood

Expertise: Curriculum Expert

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.