Calculating Gravitational Potential (OCR A Level Physics): Revision Note

Exam code: H556

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Calculating Gravitational Potential

Calculating Gravitational Potential

  • Gravitational potential Vg can be calculated at a distance r from a point mass M using the equation: 

Vg=GMr

  • Where:

    • Vg = gravitational potential (J kg–1)

    • G = Newton’s gravitational constant (N m2 kg–2)

    • M = mass of the body causing the gravitational field (kg)

    • r = distance from the centre of mass of M to the point in the field (m)

  • This means that the gravitational potential is negative on the surface of a mass (such as a planet), and increases with distance from that mass (becomes less negative toward zero)

  • Work has to be done against the gravitational pull of the planet to take a unit mass away from the planet

  • The gravitational potential at a point depends on the mass of the object producing the gravitational field and the distance the point is from that mass

Changes in Gravitational Potential

  • Two points at different distances from a mass will have different gravitational potentials

    • This is because the gravitational potential increases with distance from a mass

  • Therefore, there will be a gravitational potential difference between the two points

    • This is represented by the symbol ΔV

  • ΔV can therefore be expressed as the difference between the 'final' gravitational Vf potential and the 'initial' gravitational potential Vi  

ΔV = Vf – Vi

  • Therefore, the change in potential between two points a distance r1 and r2 from some mass M is given by:

ΔV=GMr2(GMr1)

  • This simplifies to:

ΔV=GM (1r11r2) 

  • Where:

    • ΔV = change in potential (J kg–1)

    • G = Newton’s gravitational constant (N m2 kg–2)

    • M = mass causing the gravitational field (kg)

    • r1 = initial distance from mass M (m)

    • r2 = final distance from mass M (m)

Worked Example

Calculate gravitational potential at the surface of Mars. 

Radius of Mars = 3400 km

Mass of Mars = 6.4 × 1023 kg

Answer:

Step 1: Write the gravitational potential equation

Vg=GMr

Step 2: Substitute known quantities

Vg=(6.67×1011)×(6.4×1023)3400×103= – 1.3 × 107 J kg–1

Examiner Tips and Tricks

The equation for gravitational potential in a radial field looks very similar to the equation for gravitational field strength in a radial field, but there is a very important difference! Remember, for gravitational potential: 

Vg=GMr so Vg1r

However, for gravitational field strength: 

g=GMr2 so g1r2

Additionally, remember that both Vg and g are measured from the centre of the mass M causing the field! 

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.