Accumulation Functions (College Board AP® Calculus BC): Revision Note

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Accumulation functions

What is an accumulation function?

  • An accumulation function is a function that outputs values which

    • represent an accumulation of change

    • over an interval from a given starting point

      • to a variable endpoint

    • E.g. if a strawberry harvester gathers half a kilogram of strawberries for each meter of strawberry plants (rate of change = 0.5 kilograms per meter)

      • Then the accumulation function from the harvester's starting point,

      • to a point x meters from that starting point,

      • is simply 0.5x

    • Substituting in a value for x gives you the amount of strawberries harvested up to that point

How do I write an accumulation function as a definite integral?

  • Most often you will see accumulation functions written as definite integrals:
    g(x)=axf(t) dt

    • g here is the accumulation function

      • g is a function of x

        • Its value changes as the value of x changes

    • f is the associated rate of change function

    • a is the (fixed) starting point of the integral

    • x is the (variable) ending point of the integral

    • t is merely a 'dummy variable' used for evaluating the integral

      • Any letter except x can be used for the dummy variable inside the integral

  • g(x) is calculating the accumulation of change as t goes from a to x

A graph showing an example of a rate of change function and its associated accumulation function
  • Note here that a definite integral is being used to define a new function of x

    • If f is a function of x defined by f(x)

    • Then g defined by g(x)=axf(t) dt is another function of x

Worked Example

Let f be the function defined by f(x)=2x+sinx.

Let g be the function defined by g(x)=0x f(t) dt.

(a) Show that  g(x)=x2cosx+1.

(b) Let r be a quantity for which f(x) is the rate of change function. Explain why r(x) is not necessarily equal to g(x).

Answer:

(a)

We need to integrate f with respect to t, and then evaluate the definite integral between 0 and x

0x f(t) dt=0x (2t+sint) dt=[t2cost]0x=(x)2cos(x)((0)2cos(0))=x2cosx(01)=x2cosx+1

Therefore  g(x)=x2cosx+1

(b)

g(x) is an accumulation of change, and only tells us how much r(x) changes between 0 and x

It will only be equal to r(x) if r(0)=0

g(x) tells us the change in r between 0 and x

To find the value of r(x) we need to add g(x) to the value of r when x=0, i.e. r(x)=g(x)+r(0)

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.