Convergent & Divergent Infinite Series (College Board AP® Calculus BC): Revision Note

Roger B

Written by: Roger B

Reviewed by: Mark Curtis

Updated on

Sequences & series

What is a sequence?

  • A sequence is an ordered collection of numbers

    • 'Ordered' means that there is a first number, second number, third number, etc.

    • Each number in a sequence is referred to as a term

    • For example, the sequence 12, 14, 18, 116, ...

      • 12 is the first term, 14 is the second term, etc.

  • A sequence is also a function whose domain is the positive natural numbers (1, 2, 3, 4, ...)

    • It may (but will not always) be possible to write the function explicitly as an expression in the term number n

    • For example, the sequence above can be written as an=a(n)=12n

      • where n=1, 2, 3, 4, ...

    • a1=12, a2=14, etc.

  • A sequence may also be denoted using brackets

    • For example, the sequence {an}

      • where {an}={a1, a2, a3, ..., an, ...}

  • For this course all sequences are assumed to be infinite

    • I.e. n goes from 1 to infinity

  • Note that it is also possible to begin a sequence with n=0

    • I.e. so that {an}={a0, a1, a2, ..., an, ...}

      • a0 is the first term, a1 is the second term, etc.

      • This might make the formula for an easier to write

    • If this is the case, it will be made clear in the question

What is a series?

  • A series is the sum of all the terms in a sequence

    • For example the sum sum for blank of a subscript n equals sum from n equals 1 to infinity of a subscript n equals a subscript 1 plus a subscript 2 plus a subscript 3 plus... plus a subscript n plus... is the series associated with the sequence {an}

    • Note that this is the sum of an infinite number of terms

Convergent & divergent infinite series

What is a sequence of partial sums?

  • There is a sequence of partial sums, {sn}={s1, s2, s3, ...}, associated with each series

    • sn in each case is the sum of the first n terms of the sequence that underlies the series

      • s1=a1

      • s2=a1+a2

      • s3=a1+a2+a3, etc.

What does it mean for a series to converge or diverge?

  • The series sum for blank of a subscript n converges if its associated sequence of partial sums converges

    • I.e. if the limit limnsn exists and is non-infinite

    • In this case the series sum gets closer and closer to a fixed value as more and more terms are added

  • If limnsn=S, where S is a real number, then we say that n=1an=S

    • I.e. the sum of the infinite series is equal to S

  • If a series does not converge, then it diverges

    • I.e. the sum never settles down to a single fixed finite value, no matter how many terms are added on

Examiner Tips and Tricks

It can be useful to consider some examples of sequences of partial sums that either do or do not converge. For example:

  • {sn}=1, 2, 3, 4, 5, 6, ...

    • Even though the 'gaps' between the terms are not getting bigger, the terms themselves are still getting bigger and bigger

    • So limnsn diverges to +

  • {sn}=1, 0, 1, 0, 1, 0, ...

    • Although the terms do not become unbounded (each one is only ever equal to 0 or 1), the sequence never 'settles down' to a single value

    • So limnsn does not exist

  • {sn}=5, 5, 5, 5, 5, 5, ...

    • Every term in the sequence is equal to 5, regardless of the value of n

    • So limnsn=5

  • {sn}=2, 4, 8, 16, 32, 64, ...

    • This is an alternating sequence (the terms switch signs from one term to the next)

    • The 1st, 3rd, 5th, ... terms are all positive and increase without bound

      • while the 2nd, 4th, 6th, ... terms are all negative and increase in the negative direction without bound

    • So limnsn does not exist

Worked Example

Let {an} be the sequence defined by an=12n for n=1, 2, 3, .... Further, let {sn} be the associated sequence of partial sums.

(a) Write down the value of a6.

(b) Find the values of s1, s2 and s3.

(c) Given that sn=2n12n, find the value of n=1an.

Answer:

(a)

Just substitute n=6 into the formula

a6=126=164

164

(b)

These are the sums of the first 1, 2 and 3 terms respectively

s1=a1=121=12

s2=a1+a2=121+122=12+14=34

s3=a1+a2+a3=121+122+123=12+14+18=78

s1=12,   s2=34,   s3=78

(c)

Rewrite the expression

sn=112n

Take the limit as n tends to infinity

limnsn=limn(112n)=1limn(2n)=10=1

Use n=1an=limnsn

n=1an=1

Algebra of convergent series

How can I combine results for convergent infinite series?

  • If n=1an and n=1bn are both convergent series, and if c and d are constants, then the following results are true

    • n=1can=c n=1an

    • n=1(an±bn) = n=1an ± n=1bn

    • n=1(can±dbn) = cn=1an ± dn=1bn

      • The third result is just the combination of the first two

      • It can be extended to sums or differences of more than two series

  • These results are not valid for divergent series

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Mark Curtis

Reviewer: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.