Properties of Definite Integrals (College Board AP® Calculus BC): Revision Note

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Definite integrals

What is a definite integral?

  • A definite integral is written in the form

    • abf(x) dx

      • f(x) is the function being integrated (also known as the integrand)

      • dx indicates that the function is being integrated with respect to x

      • a and bare the integration limits

        • the function is integrated 'from a to b'

      • You'll most often see definite integrals with ab

        • But integrals with a>b are also valid

  • A definite integral can be interpreted in a number of ways

    • It is a mathematical operation that outputs a number

      • based on f(x) and the values of a and b

    • If f(x) is interpreted as a rate of change function

      • then the definite integral is the accumulation of change as x goes from a to b

    • On the graph of y=f(x), where f(x)0 on the interval [a, b]

      • the definite integral gives the area between y=f(x)and the x-axis, between x=a and x=b

A graph of a function y=f(x), showing the area under the curve between x=a and x=b as a definite integral

How is a definite integral defined as a limit of Riemann sums?

  • The value of a definite integral can be defined as a limit of Riemann sums:

    • abf(x) dx=limmax Δxi0 i=1nf(xi)Δxi

      • n is the number of subintervals used for the sum

        • This is the same as the number of rectangles

      • xi is a value of x in the ith subinterval

        • note that this is any value in the ith subinterval

      • Δxi is the width of the ith subinterval

        • i.e. the width of the ith rectangle

      • limmax Δxi0 means the limit as the width of the largest subinterval (and hence of all subintervals) approaches zero

    • As the subintervals (and rectangles) get narrower and narrower

      • the area of the approximating rectangles gets closer and closer to the exact area under the curve

A graph of a function y=f(x) showing some of the quantities used when defining a definite integral as a limit of Riemann sums
  • Note that having the width of the largest subinterval approach zero

    • is equivalent to having the number of subintervals approach infinity

  • Therefore the Riemann sum limit for a definite integral can also be written with n as the limit index

    • abf(x) dx=limn i=1nf(xi)Δxi

      • If the subintervals are assumed to be of equal width, then expressions for f(xi) and Δxi can be written in terms of a, b and n

      • See the Worked Example

Examiner Tips and Tricks

You are not expected to work out the value of a definite integral using the limit of Riemann sums!

  • See the 'Evaluating Definite Integrals' study guide for the method that is usually used

But you should be able to recognize limit and definite integral expressions that are equivalent

Worked Example

Evaluate the following limit

limn i=1n((3+5ni)2+1)·(5n)

Answer:

The trick here is recognizing this as a limit of Riemann sums

The key term is 5n

  • For a Riemann sum with equal subintervals and a total interval width of 5, this is the width of the ith subinterval

    • I.e. ba=xnx0=5

    • and Δxi=5n

  • If the total interval starts at -3, then  x0=3,  x1=3+5n, x2=3+5n·2, etc.

    • I.e. a=3

    • b=3+5=2

    • and  xi=3+5ni

  • This means (3+5ni)2+1 can be interpreted as f(xi)

    • I.e. f(x)=x2+1

  • Note that the sum is set up in the form of a right Riemann sum

    • I.e. with xi=xi

    • But as  Δxi0 the type of Riemann sum used becomes insignificant

Recognizing all of this means the limit can be rewritten as a definite integral

limn i=1n((3+5ni)2+1)·(5n)=32(x2+1) dx

The value can be worked out by evaluating the definite integral

32(x2+1) dx=[x33+x]32=(2)33+(2)((3)33+(3))=143(12)=503

limn i=1n((3+5ni)2+1)·(5n)=503

Definite Integrals of sums, differences and constant multiples

What are the properties of sums, differences and constant multiples of definite integrals?

  • These are related to the equivalent properties for indefinite integrals

Definite integral of a constant times a function

  • If k is a constant, then

    • abkf(x) dx=kabf(x) dx

      • I.e. the constant can be brought out in front of the integral as a multiplier

Definite integral of a sum or difference of functions

  • If f and g are two functions being integrated over the same interval, then

    • ab(f(x)±g(x)) dx=abf(x) dx±abg(x) dx

      • I.e. the integral of a sum (or difference) is equal to the sum (or difference) of integrals

Changing limits of integration

What are the definite integral properties involving integration limits?

  • There are three properties you should know here

Definite integral of a zero-length interval

  • For any function f

    • aaf(x) dx=0

      • I.e. if the top and bottom integration limits are equal, the definite integral is equal to zero

Reversing the limits of integration

  • For a function f

    • baf(x) dx=abf(x) dx

      • I.e. reversing the integration limits 'flips' the sign of the value of the definite integral

Definite integrals on adjacent intervals

  • For a function f, and for c such that acb

    • abf(x) dx=acf(x) dx+cbf(x) dx

      • I.e. the sum of definite integrals over adjacent subintervals of

        [a, b] is equal to the total definite integral from a to b

Worked Example

f is a function such that 25f(x) dx=3 and 27f(x) dx=12.

g is a function such that 57g(x) dx=2.

Find the value of 75(f(x)3g(x)) dx.

Answer:

First use the sum, difference and constant multiple properties

75(f(x)3g(x)) dx=75f(x) dx375g(x) dx

From the reversing the limits of integration property, we know that 75f(x) dx=57f(x) dx and 75g(x) dx=57g(x) dx

75(f(x)3g(x)) dx=57f(x) dx+357g(x) dx

Use the adjacent intervals property to find 57f(x) dx

27f(x) dx=25f(x) dx+57f(x) dx12=3+57f(x) dx57f(x) dx=15

Now we have all the values we need

75(f(x)3g(x)) dx=57f(x) dx+357g(x) dx=(15)+3(2)=9

75(f(x)3g(x)) dx=9

Worked Example

The graph of f', consisting of two straight line segments and a semicircle

The function f is defined on the closed interval [0, 9] and satisfies f(5)=2. The graph of f', the derivative of f, consists of two line segments and a semicircle, as shown in the figure.

Find

(a)  f(9)

(b)  f(0)

Answer:

(a)

The value of f at 9 will be the value at 5, plus the accumulation of change between 5 and 9

f(9)=f(5)+59f'(x) dx

The integral of f' from 5 to 9 is the area of a semicircle of radius 2; but because f' is below the x-axis the value of the definite integral will be negative

f(9)=2+(12·π(2)2)=22π

f(9)=22π

(b)

The value of f at 0 will be the value at 5, plus the accumulation of change between 5 and 0; i.e. going 'backwards' along the x-axis

f(0)=f(5)+50f'(x) dx

Use the 'reversing the limits of integration' property

f(0)=f(5)05f'(x) dx

The integral of f' from 0 to 5 is the area of a rectangle of width 2 and height 5, and a right triangle of base 3 and height 5

f(0)=2(2·5+12·3·5)=2352=392

f(0)=392

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.