Asymptotes (College Board AP® Calculus BC): Study Guide

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Horizontal asymptote

What is a horizontal asymptote?

  • A horizontal asymptote is a horizontal line

    • that the graph of a function gets closer and closer to (but never touches or intersects)

    • as x becomes unbounded in the positive or negative direction

  • On the following diagram, the horizontal asymptote is indicated by a dashed line

A graph of a function f with a horizontal asymptote at y=c
An example of a function with a horizontal asymptote at y=c

How can I identify horizontal asymptotes using limits?

  • A function will have a horizontal asymptote if it has a finite limit at infinity

    • I.e. the line y=c will be a horizontal asymptote for the graph of a function f if

      • limxf(x)=c, or

      • limxf(x)=c

  • Horizontal asymptotes (if any) may therefore be determined by evaluating the limits at infinity

Examiner Tips and Tricks

By graphing a function on your graphing calculator you can:

  • spot any asymptotic behavior by a function at plus or minus infinity

  • check limits that you have determined analytically

How can I identify horizontal asymptotes numerically?

  • If a function has a horizontal asymptote, then its values will tend to a limit for large positive or negative values of x

  • Consider, the function  f(x)=12+5ex10001+ex1000

  • Consider the values for large positive x

x=

 12+5ex10001+ex1000=

100

8.674...

1,000

10.117...

10,000

11.999...

100,000

12

  • The table suggests that limxf(x)=12

    • Note  f(100 000)12

    • It starts as 11.999... with a large number of 9s

    • Most calculators cannot differentiate between this value and 12

  • Consider the values for large negative x

x=

 12+5ex1001+ex100=

-100

8.325...

-1,000

6.882...

-10,000

5.000...

-100,000

5

  • The table suggests that limxf(x)=5

    • Note  f(100 000)5

    • It starts as 5.000... with a large number of 0s

    • Most calculators cannot differentiate between this value and 5

Vertical asymptote

What is a vertical asymptote?

  • A vertical asymptote is a vertical line

    • that the graph of a function gets closer and closer to (but never touches or intersects)

    • as x gets closer and closer to the x-value of the vertical line

  • On the following diagram, the vertical asymptote is indicated by a dashed line

Graph of a function f with a vertical asymptote at x=c
An example of a function with a vertical asymptote at x=c

How can I identify vertical asymptotes using limits?

  • A function will have a vertical asymptote at any x-value where the function becomes unbounded

    • I.e. the line x=c will be a vertical asymptote for the graph of a function f if

      • limxcf(x)=±, or

      • limxc+f(x)=±

  • Vertical asymptotes (if any) may therefore be determined by identifying points where the function becomes unbounded

    • Usually this will involve a function in the form of a quotient

      • at points where the denominator becomes zero

How can I identify vertical asymptotes numerically?

  • If a function has a vertical asymptote, then its values tend to positive or negative infinity as the values of x get closer to the vertical asymptote

  • Consider, the function  f(x)=cscx

  • Consider the values for values of x just smaller than 0

x=

 cscx=

-0.1

-10.016...

-0.01

-100.001...

-0.001

-1,000.000...

-0.0001

-10,000.000...

  • The table suggests that limx0f(x)=

    • The values of  f keep getting further from 0 as x gets closer to 0

  • Consider the values for values of x just bigger than 0

x=

 cscx=

0.1

10.016...

0.01

100.001...

0.001

1,000.000...

0.0001

10,000.000...

  • The table suggests that limx0+f(x)=

    • The values of  f keep getting further from 0 as x gets closer to 0

Worked Example

Let f be the function defined by f(x)=3x11x2.

Using limits, identify the vertical and horizontal asymptotes (if any) on the graph of f.

Answer:

The denominator becomes 0 when x=2, so start by considering the limits there

At 2 the numerator is equal to -5, so zero only occurs in the denominator

Just 'to the left' of 2, 3x11<0 and x2<0 so

limx2f(x)=

Just 'to the right' of 2, 3x11<0 and x2>0 so

limx2+f(x)=

This confirms that the graph of f has a vertical asymptote at x=2

To identify horizontal asymptotes, start by rearranging to make the behavior of the function more obvious

3x11x2=3(x2)5x2=3(x2)x25x2=35x2

5x2 becomes closer and closer to zero as x increases in the positive or negative directions, so

limxf(x)=limxf(x)=30=3

Alternatively, divide the top and bottom of the function by x

limxf(x)=limx311x12x=31=3

limxf(x)=limx311x12x=31=3

This means that the graph of f has a horizontal asymptote at y=3

The graph of f has a vertical asymptote at x=2, and a horizontal asymptote at y=3

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.