Derivative Rules (College Board AP® Calculus BC): Study Guide

Jamie Wood

Written by: Jamie Wood

Reviewed by: Dan Finlay

Updated on

Power rule

How do I differentiate powers of x?

  • Powers of x are differentiated according to the following formula:

    • If f(x)=xn then f'(x)=n·xn−1 

    • This applies where n∈ℝ (real)

  • This can also be written using the notation for differentiation with respect to x

    • ddx(xn)=n·xn−1

  • For example, if f(x)=x7

    • f'(x)=7x7−1=7x6

  • Be extra careful with fractional or negative powers, for example:

    • If g(x)=x23 then g'(x)=23x23−1=23x−13

    • If h(x)=x−3 then h'(x)=−3x−3−1=−3x−4

  • This is much quicker than using the definition of a derivative, limh→0f(x+h)−f(x)h

    • However you should still be able to use this definition to find a derivative

Worked Example

Find the derivative of the function f(x)=x3,

(i) by using the power rule,

(ii) by using the definition of a derivative.

Answer:

(i)

If f(x)=xn then f'(x)=nxn−1 

f'(x)=3x3−1=3x2

f'(x)=3x2

(ii)

Use the definition of a derivative limh→0f(x+h)−f(x)h

f(x)=x3 so this means f(x+h)=(x+h)3

f'(x)=limh→0(x+h)3−x3h

Expand the bracket and simplify

f'(x)=limh→0x3+3x2h+3xh2+h3−x3h=limh→03x2h+3xh2+h3h=limh→0(3x2+3xh+h2)=3x2+3x·0+02

Simplify

f'(x)=3x2

Derivatives of sums, differences and constant multiples

How do I differentiate sums and differences?

  • To differentiate a sum or difference of functions:

    • Differentiate each function individually

    • Take the sum or difference of the derivatives

  • This can be written as:

    • ddx(f(x)±g(x))=ddx(f(x))±ddx(g(x))

  • For example, if f(x)=x3+x7−x12+x12

    • Then f'(x)=3x2+7x6−12x11+12x−12

Examiner Tips and Tricks

Note that products and quotients of powers of x cannot be differentiated in this way; they may need to be expanded or simplified first.

How do I differentiate functions that have been multiplied by a constant?

  • To differentiate a function that has been multiplied by a constant:

    • Differentiate the function

    • Multiply it by the constant

  • This can be written as:

    • ddx(k·f(x))=k·ddx(f(x))

  • Constant multiples of powers of x are differentiated according to the following formula:

    • If f(x)=axn then f'(x)=a·nxn−1 

  • For example, if f(x)=12x4

    • f'(x)=12×4x3=48x3

  • Be careful with negative numbers

    • If g(x)=−3x−7 then g'(x)=−3×−7x−8=21x−8

  • This can then be applied to sums and differences

    • E.g. If h(x)=2x4+7x−5−3x8

    • Then h'(x)=8x3−35x−6−24x7

    • This is especially useful when differentiating polynomials

How do I differentiate linear and constant functions?

  • If f(x)=ax then f'(x)=a

    • You can derive this by writing the function as f(x)=ax1

      • f'(x)=1·ax0=a

    • You can also see this graphically by considering the slope of a straight line

      • It is a constant value

    • E.g. If f(x)=4x then f'(x)=4

      • This can also be seen graphically as the slope of the line y=4x is 4

  • If g(x)=a then g'(x)=0

    • You can derive this by taking the limit of the difference quotient formula

      • g'(x)=limh→0g(x+h)−g(x)h=limh→0a−ah=0

    • You can also see this graphically by considering the slope of a horizontal line

      • It is zero

    • E.g. If g(x)=2 then g'(x)=0

Worked Example

The function f(x) is defined by f(x)=2x32+5x−3−9x+7.

Find the derivative of f(x).

Answer:

Differentiate each term individually and sum them together

Be especially careful with fractions and negatives

f'(x)=2×32x12 + 5×−3x−4 − 9 + 0

Simplify

f'(x)=3x12−15x−4−9

Simplifying expressions to find derivatives

How do I simplify an expression before differentiating?

  • If the function is not simply a sum of multiples of xn, it may need to be simplified before it can be differentiated

  • You may need to expand

    • E.g. f(x)=(x+2)(2x2+5)

    • Expand the brackets

      • f(x)=2x3+4x2+5x+10

    • This is now a sum of multiples of xn

    • Differentiate each term

      • f'(x)=6x2+8x+5

  • You may need to rewrite the expression as a power of x using laws of exponents

    • E.g. g(x)=9x4×x3x2

    • Simplify using laws of exponents

      • g(x)=9x7x2=9x5

      • This can now be differentiated

        • g'(x)=45x4

    • Also consider h(x)=2x

    • Rewrite using laws of exponents

      • h(x)=2x12=2x−12

    • This can now be differentiated

      • h'(x)=−x−32

Worked Example

Find the derivatives of the following functions.

(a) f(x)=(4x−3)(6x+2x)

(b) g(x)=2x−6xx2

Answer:

(a)

Expand the brackets and simplify

f(x)=24x2+8−18x−6x

Rewrite the term 6x as a power of x

f(x)=24x2+8−18x−6x−1

Differentiate each term

f'(x)=48x−18+6x−2

(b)

Rewrite the square root as a power

g(x)=2x−6x12x2

Simplify using laws of exponents

g(x)=2xx2−6x12x2=2x−1−6x−32

Differentiate each term

g'(x)=−2x−2+9x−52

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Jamie Wood

Author: Jamie Wood

Expertise: Curriculum Expert

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.