Disc Method Around Other Axes (College Board AP® Calculus BC): Study Guide

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Updated on

Volume with disc method revolving around other axes

How can I use the disc method to calculate volumes of revolution around axes parallel to the x-axis?

  • For a continuous function f, if the region bounded by

    • the curve y=f(x) and the line y=k

    • between x=a and x=b

  • is rotated 2π radians (360°) around the line y=k, then the volume of revolution is

    •  V=πab(yk)2 dx

      • Note that y here is a function of x

  • Thinking of this as an accumulation of change

    • π(yk)2·x is the volume of a disc with

      • circular cross section of radius |yk|

      • and length x

    • π(yk)2 dx is the limit of this volume element as x0

    • The integral abπ(yk)2 dx sums up all these infinitesimal volume elements between x=a and x=b

Worked Example

Let R be the region enclosed by the graph of f(x)=1+ex, the lines x=1 and x=3, and the line y=2, as shown in the figure below.

Graph showing a shaded region R bounded by the curve y=1+e^(-x) and the lines x=1, x=3, and y=-2

Find the volume of the solid generated when R is rotated about the horizontal line y=2.

Answer:

Use V=πab(yk)2 dx

V=π13((1+ex)(2))2 dx=π13(3+ex)2 dx=π13(9+6ex+e2x) dx=π[9x6ex12e2x]13=π(186e312e6+6e1+12e2)=62.753258...

62.753 units cubed (to 3 decimal places)

How can I use the disc method to calculate volumes of revolution around axes parallel to the y-axis?

  • This is similar to finding volumes of revolution around axes parallel to the x-axis

  • For a continuous function f, if the region bounded by

    • the curve y=f(x) and the line x=k

    • between y=a and y=b

  • is rotated 2π radians (360°) around the line x=k, then the volume of revolution is

    •  V=πab(xk)2 dy

      • Note that x here is a function of y

        • This will mean rewriting y=f(x) in the form x=g(y)

      • Also note that the integration is done with respect to y

Worked Example

Let R be the region enclosed by the graph of f(x)=ln(x3), the lines y=2 and y=1, and the line x=1, as shown in the figure below.

Graph depicting a shaded region R bounded by the curve y=ln(x-3), the lines y=-2 and y=-1, and the line x=1.

Find the volume of the solid generated when R is rotated about the vertical line x=1.

Answer:

Use V=πab(xk)2 dy

First rewrite the function as a function of y

y=ln(x3)ey=x3x=3+ey

Now that can be put into the integral

Note that the integration will be along the y-axis, from y=2 to y=1

V=π21((3+ey)1)2 dy=π21(2+ey)2 dy=π21(4+4ey+e2y) dy=π[4y+4ey+12e2y]21=π(12+4e+12e24e212e4)=81.735307......

81.735 units cubed (to 3 decimal places)

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Roger B

Author: Roger B

Expertise: Development Editor

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.