Defining Parametric Equations (College Board AP® Calculus BC): Study Guide

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Updated on

Defining parametric equations

What are parametric equations?

  • Parametric equations are an alternative way to represent the equation of a curve using a third variable called a parameter

    • The letter t is often used for the parameter

    • The parametric equations are

      • x=f(t)

      • y=g(t)

  • For example

    • x=t5

    • y=t2+et

  • Sometimes a restricted range of t values is given

    • e.g. where 0t8

How do I sketch parametric equations?

  • You can sketch parametric curves using your calculator

    • Change the type of graph to "parametric"

  • Parametric curves often have very interesting shapes

    • They can loop around and spiral etc.

Six graphs of parametric equations with x and y axes: including a circle, horizontal ellipse, spiral, a loop, a four-leaf rose and graph with cusps.
Examples of parametric curves
  • Parametric curves have a direction of flow

    • e.g. anticlockwise around a loop

    • The direction can be found by looking at the equations as t increases

  • You can find key features of the graph algebraically

    • The y-intercepts are when x=0

      • If x=f(t) then solve f(t)=0

    • The x-intercepts are when y=0

      • If y=g(t) then solve g(t)=0

Examiner Tips and Tricks

If parametric equations involve trig functions (e.g. sin t) then you should plot in radians on your calculator.

How do I eliminate the parameter?

  • Eliminating the parameter means rewriting a parametric curve as an equation in x and y only (no t)

    • To do this:

      • Make t the subject of one of the equations

      • Substitute this into the other equation

      • Simplify if required

    • e.g. make t the subject of x=t5 and substitute it into y=t2+et

      • This gives y=(x+5)2+ex+5

      • There is no t

  • You may need to convert a range of t values into a range of x or y values

    • See the Worked Example

  • It is not always possible to eliminate the parameter

    • e.g. x=t+et and y=sin t+ln t

    • If it is possible, it is not always possible to make y the subject

      • e.g. yey=x+1

How do I use trigonometric identities to eliminate the parameter?

  • Another way to eliminate the parameter is by substituting parametric equations into a trigonometric identity

    • e.g. rearrange and substitute x=2+sin t and y=4 cos t into the identity sin2 t+cos2 t=1

      • This gives the equation (x2)2+(y4)2=1

      • There is no t

Worked Example

A curve is given parametrically by

x=3ety=2+t

where 0t2

(a) Find the coordinates of any points at which the curve intersects the coordinate axes.

(b) Sketch the curve. Indicate the direction of the curve as t increases.

(c) Find the equation of the curve in the form y=f(x).

Answer:

(a)

To find any points of intersection with the x-axis, y must equal zero

2+t=0

Solve this equation to find t

t=2

However you are told 0t2 so t=2 is not possible (there is no x-intercept)

To find any points of intersection with the y-axis, x must equal zero

3et=0

Solve this equation to find t

et=3t=ln 3

Since ln 3=1.0986... this value of t is in the range 0t2

Substitute t=ln 3 into the equation for y to find its coordinate

y=2+ty=2+ln 3

The only point at which the curve crosses the coordinate axes is (0, 2+ln 3)

(b)

Change the input in your calculator to "parametric" and use it to sketch the graph for 0t2

The direction can be found by looking at the coordinates of two points as t increases, e.g. t=0 and t=2

When t=0 then x=3e0=31=2 and y=2+0=2, and when t=2 then x=3e2(=4.389056...) and y=2+2=4

t=0 gives coordinates (2, 2)

t=2 gives coordinates (3e2, 4)

So direction of flow is from (2, 2) to (3e2, 4)

Graph of parametric equations x = 3 - e^t and y = 2 + t showing a curved line with arrows, dashed lines to axes, and marked points.

(c)

The form asked for has no t in it, so make t the subject of one of the equations and substitute it into the other

For example, make t the subject of the x equation

x=3etet=3xt=ln(3x)

Then substitute this into the y equation

y=2+ty=2+ln(3x)

The interval 0t2 needs to be turned into a interval of x values (for example, by looking at the x-axis in the graph above)

y=2+ln(3x) where 3e2x2

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Mark Curtis

Author: Mark Curtis

Expertise: Maths Content Creator

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.