Percentage Increases & Decreases (Edexcel IGCSE Maths A: Higher): Revision Note

Exam code: 4MA1

Percentage increases & decreases

How do I increase by a percentage?

  • A percentage increase makes an amount bigger by adding that percentage on to itself

  • With a calculator you can use multipliers

    • A multiplier is the decimal equivalent of a percentage

      • percentage can be converted to a decimal by dividing by 100

    • When increasing by a percentage, we are finding a percentage greater than 100%

    • To increase 80 by 15%

      • We are finding 115% of 80, so the multiplier is 1.15

      • 1.15 × 80 = 92

  • You can also use the basic percentages methods to find the percentage you are increasing by

    • Then add this on to the original amount 

    • To increase 30 by 10%

      • 10% of 30 is 3

      • 30 + 3 = 33

      • This is equivalent to finding 110% of 30

How do I decrease by a percentage?

  • A percentage decrease makes an amount smaller by subtracting that percentage from itself

  • With a calculator you can use multipliers

    • When decreasing by a percentage, we are finding a percentage smaller than 100%

    • To decrease 80 by 15%

      • We are finding 85% of 80, so the multiplier is 0.85

        • Because 100% - 15% = 85%

      • 0.85 × 80 = 68

  • You can also use the methods outlined in Basic Percentages to find the percentage you are decreasing by

    • Then subtract this from the original amount 

    • To decrease 30 by 10%

      • 10% of 30 is 3

      • 30 - 3 = 27

      • This is equivalent to finding 90% of 30

        • Because 100% - 10% = 90%

Worked Example

(a) Increase 200 kg by 21%.

Answer:

An increase by 21% is equivalent to finding 121% of the original amount
So the multiplier is 1.21 

1.21 × 200

242 kg

(b) An item that costs $500 is discounted by 35%.

Find the new price of the item.

Answer:

A discount of 35% means the price decreases by 35%

A decrease of 35% is equivalent to finding 65% of the original amount (100 - 35 = 65) 
So the multiplier is 0.65

500 × 0.65

$325 

How do I deal with repeated percentage changes?

  • In some problems there may be several changes by a percentage

  • For example,

    • A shop increases the price of a product costing £80 by 10%,

      • equivalent to a multiplier of × 1.10

    • and then discounts the product by 15%,

      • equivalent to a multiplier of × 0.85

    • and then discounts the product by a further 20%

      • equivalent to a multiplier of × 0.80

  • You can either:

    • Multiply the starting amount by each multiplier in turn

      • ( ( ( 80 × 1.10 ) × 0.85 ) × 0.80 ) = £59.84

    • Or combine the multipliers first and then multiply by the "combined multiplier"

      • 1.10 × 0.85 × 0.80 = 0.748

        • This shows it is equivalent to 74.8% of the original amount, or a discount of 25.2%

      • 80 × 0.748 = £59.84

  • In general, for n multipliers of values m1, m2, ... , mn

    • The combined multiplier is m1 × m2 × ... × mn

How do I find a percentage change?

  • The multiplier that was used for a percentage change can be found using the formula:

    • m=Amount afterAmount before

  • The value of m corresponds to the multiplier for the percentage change

    • A value greater than 1 is a percentage increase

      • 1.05 corresponds to an increase by 5%

    • A value less than 1 is a percentage decrease

      • 0.75 corresponds to a decrease by 25%

  • Alternatively you can use the formula:

    • Percentage Change = After  BeforeBefore×100

    • A positive value is a percentage increase

      • An answer of 12 means an increase of 12%

    • A negative value is a percentage decrease

      • An answer of -28 means a decrease of 28%

How do I find a percentage profit or loss?

  • Similar strategies to the above can be used to find the percentage profit or loss

  • Shops buy or produce items at a "cost price" and sell them at a "selling price"

  • Using a multiplier method:

    • m=Selling PriceCost Price

    • A value greater than 1 is a profit

      • 1.05 corresponds to a 5% profit

    • A value less than 1 is a loss

      • 0.75 corresponds to a 25% loss

  • Alternatively you can use the formula:

    • Percentage Profit = Selling Price  Cost PriceCost Price×100

    • A positive value is a profit

      • An answer of 12 means a 12% profit

    • A negative value is a loss

      • An answer of -28 means a 28% loss

Examiner Tips and Tricks

  • Use "common sense" to check your answer!

    • If an item is sold for more than it was bought for, you are expecting a profit, not a loss

Worked Example

The number of students in a school changes from 250 to 310.

Describe the percentage change in number of students.

Answer:

Method 1
Use the formula m=Amount afterAmount before

310250=1.24 

This multiplier is greater than 1, so corresponds to a percentage increase

A percentage increase of 24%

Method 2
Use the formula Percentage Change = After  BeforeBefore×100

310250250×100=24

The value is positive, so this is a percentage increase

A percentage increase of 24%

Worked Example

Sophie purchases a car for $8000 and sells it several years later for $5600.

Describe the percentage profit or loss on the car. 

Answer:

Method 1
Use the formula m=Selling PriceCost Price

56008000=0.7

The value is less than 1 so means it is a percentage loss

The selling price was 70% of the cost price, so a loss of 30%

A loss of 30%

Method 2
Use the formula Percentage Profit = Selling Price  Cost PriceCost Price×100

560080008000×100=30

The value is negative, so this is a percentage loss

A loss of 30%

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Jamie Wood

Author: Jamie Wood

Expertise: Curriculum Expert

Jamie graduated in 2014 from the University of Bristol with a degree in Electronic and Communications Engineering. He has worked as a teacher for 8 years, in secondary schools and in further education; teaching GCSE and A Level. He is passionate about helping students fulfil their potential through easy-to-use resources and high-quality questions and solutions.

Dan Finlay

Reviewer: Dan Finlay

Expertise: Portfolio Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.