Transfer of Biomass (AQA GCSE Biology): Revision Note
Exam code: 8461
Biomass transfer
When primary consumers consume (eat) producers, they break down the biomass of the producer (digestion) and use the chemical energy to increase or sustain their own biomass
When secondary consumers consume (eat) primary consumers, they break down the biomass of the primary consumer (digestion) and use the chemical energy to increase or sustain their own biomass, and so on
In this way, as chemical energy is transferred from one trophic level to the next, biomass is also transferred
Loss of biomass
Not all biomass is transferred from one trophic level to the next
Only about 10% of the biomass of each trophic level is passed on to the next
This is why food chains are rarely made up of more than six trophic levels – the total amount of biomass available eventually becomes too small to support another trophic level

Losses of biomass are due to:
organisms rarely eat every part of the organism they are consuming – some of the biological material of plants and animals may be inedible (e.g. many predators do not consume the bones of their prey)
not all the ingested material is digested and absorbed, some is egested as faeces
some absorbed material is lost as waste.
Carbon dioxide and water are waste products of respiration (when glucose is used by an organism to provide energy for moving and keeping warm, rather than to produce more biomass)
Water and urea are the waste products in urine, which is produced when proteins are broken down

Efficiency of biomass transfers
Being able to calculate the efficiency of biomass transfers between trophic levels by percentages is an important skill for a biologist:
Worked Example
Below is a food chain with four trophic levels:
Clover → Snail → Thrush → Sparrowhawk
The total biomass of the organisms at each trophic level (kg):
Clover: 1450
Snail: 138
Thrush: 14.1
Sparrowhawk: 1.18
Question 1: Calculate the efficiency of biomass transfer from the first to the second trophic level. Give your answer to 3 significant figures.
Use the equation:
Percentage efficiency transfer = (biomass in higher trophic level ÷ biomass in lower trophic level) × 100
Answer:
Biomass of snails ÷ biomass of clover:
(138 ÷ 1450) × 100 = 9.52%
Question 2: Calculate the efficiency of biomass transfer between the remaining trophic levels. Give your answers to 3 significant figures.
Answer:
Efficiency of biomass transfer between second and third trophic levels:
(14.1 ÷ 138) × 100 = 10.2%
Efficiency of biomass transfer between third and fourth trophic levels:
(1.18 ÷ 14.1) × 100 = 8.37%
Examiner Tips and Tricks
Remember – approximately only 10% of the biomass of each trophic level is passed on to the next. This means your answer should be somewhere around 10%. Sometimes it may be a bit less than 10%, sometimes it may be a bit more than 10%
Examiner Tips and Tricks
You will be provided with the equation for calculating the efficiency of biomass transfers in the exam so don’t worry about learning it. Instead, make sure you learn how to use the equation. It is just like working out a percentage as you would normally: divide the smaller number by the bigger one and then multiply the answer by one hundred!
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