Speed-Time Graphs (Cambridge (CIE) IGCSE Physics): Revision Note
Exam code: 0625 & 0972
Speed-time graphs
A speed-time graph is used to describe the speed of an object and calculate its acceleration
Constant acceleration on a speed-time graph
If an object is moving at a constant acceleration, the speed-time graph will be a straight line
If the constant acceleration is zero, the line will be horizontal
If the constant acceleration is non-zero, the line will have a gradient
If an object has an acceleration of zero, the object is travelling at a constant speed
If the constant speed is zero, then the object is stationary
Motion on a speed-time graph

The gradient of a speed-time graph (opens in a new tab) represents the object's acceleration
A steeper slope, or a higher gradient, represents a greater acceleration
A shallower slope, or a lower gradient, represents a smaller acceleration
If the gradient is positive, the line slopes upward
A positive gradient represents an increasing speed, or acceleration
If the gradient is negative, the line slopes downward
A negative gradient represents a decreasing speed, or deceleration
Speeding up and slowing down on a speed-time graph

Plotting a speed-time graph
Follow these steps to plot a speed-time graph from data:
Label the x-axis with time and the y-axis with speed
Choose sensible scales so that the graph occupies more than half of the graph grid
Use the data given to plot points on the graph
Join the points with horizontal straight lines if the speed is constant, or sloped straight lines if the speed is not constant
Examiner Tips and Tricks
You could be asked to describe the motion of an object from data given in a question. You can read more about graph skills in the article Graph skills in GCSE Physics
Using speed-time graphs
Speed-time graphs can also be used to determine the distance travelled by an object
The area under a speed-time graph
The area under a speed-time graph represents the distance travelled

The area under a speed-time graph represents the distance travelled
If the area of a section of the speed-time graph forms a triangle, the area can be calculated using:
If the area of a section of the speed-time graph forms a rectangle, the area can be determined using:
Where:
= area of a triangle
= area of a rectangle
= base
= height
The total distance travelled can be determined by finding the total area under the speed-time graph
The distance travelled for part of the journey can be determined by finding the area under the graph for a specific time interval
Area under a speed-time graph split into sections

Worked Example
The speed-time graph below shows a car journey that lasts for 160 seconds.

Calculate the total distance travelled by the car on this journey.
Answer:
Step 1: Recall that the area under a speed-time graph represents the distance travelled
In order to calculate the total distance travelled, the total area underneath the graph must be determined
Step 2: Identify each enclosed area
In this example, there are five enclosed areas under the line
These can be labelled as areas 1, 2, 3, 4 and 5, as shown in the image below: Step 3: Calculate the area of each enclosed shape under the line
Area 1 = area of a triangle
Area 2 = area of a rectangle
Area 3 = area of a triangle
Area 4 = area of a rectangle
Area 5 = area of a triangle
Step 4: Calculate the total distance travelled by finding the total area under the line
Add up each of the five areas enclosed:
Examiner Tips and Tricks
Some areas will need to be split into a triangle and a rectangle to determine the area for a specific time interval, like areas 3 and 4 in the worked example above.
If you are asked to find the distance travelled for a specific time interval, then you just need to find the area of the section above that time interval.
For example, the distance travelled between 70 s and 90 s is the sum of Area 3 + Area 4.
In questions like this, marks would be awarded for recognising that the distance travelled is the area under the graph, calculating the area of some of the individual sections correctly, and for the final answer.
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