Acceleration (Cambridge (CIE) IGCSE Physics): Revision Note

Exam code: 0625 & 0972

Leander Oates

Written by: Leander Oates

Reviewed by: Tim

Updated on

Acceleration

Extended tier only

  • Acceleration describes how the velocity of an object changes over time

  • Acceleration is defined as:

The change in velocity per unit time 

  • In other words, acceleration is the rate of change of velocity

  • The equation for calculating acceleration is:

a = vt

  • Where:

    • a = acceleration in metres per second squared (m/s2)

    • v = change in velocity in metres per second (m/s)

    • t = time taken in seconds (s)

Formula triangle diagram split into three parts showing acceleration equation: top section has delta v, bottom left has a, bottom right has delta t.

To use a formula triangle, simply cover up the quantity you wish to calculate and the structure of the equation is revealed

 Change in velocity

  • The change in velocity is the difference between the initial and final velocity:

v = v  u

  • Where:

    • v = change in velocity in metres per second (m/s)

    • v = final velocity in metres per second (m/s)

    • u = initial velocity in metres per second (m/s)

Speeding up and slowing down

  • An object can change its velocity in several ways:

    • speeding up

    • slowing down

    • changing direction

  • Any change in an object's velocity is an acceleration

    • When an object changes direction, it is accelerating

  • Acceleration is positive if its direction is in the same direction as the motion of the object

  • When an object speeds up, it is accelerating

    • This is positive acceleration

  • When an object slows down, it is decelerating

    • This is negative acceleration

Acceleration of different objects

Diagram showing a car decelerating at −5 m/s² as it slows to a stop, alongside a rocket accelerating upwards at +30 m/s².

A rocket speeding up (accelerating) and a car slowing down (decelerating)

Worked Example

A Japanese bullet train decelerates at a constant rate in a straight line. The velocity of the train decreases from 50 m/s to 42 m/s in 30 seconds.

(a) Calculate the change in velocity of the train. [1]

(b) Calculate the deceleration of the train, and explain how your answer shows the train is slowing down. [3]

Answer:

Part (a)

Step 1: List the known quantities

  • Initial velocity, u = 50 m/s 

  • Final velocity, v = 42 m/s 

Step 2: Write the equation for change in velocity

v = v  u

Step 3: Substitute values for final and initial velocity

v = 42  50

v = 8 m/s [1 mark]

Part (b)

Step 1: List the known quantities

  • Change in velocity, v = 8 m/s 

  • Time taken, t = 30 s

Step 2: Write the equation for acceleration

 a = vt

Step 3: Substitute the values for change in velocity and time

a = 830 [1 mark]

a = 0.27 m/s2 [1 mark]

Step 4: Interpret the value for deceleration

  • The answer is negative, which indicates the train is slowing down [1 mark]

Examiner Tips and Tricks

Remember, acceleration measures how much the velocity (m/s) changes every second, so the units are metres per second squared, m/s2. If an object's acceleration is decreasing and is still positive, it is still speeding up. It will only be the rate at which the speed increases that will decrease.

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.