Kinematic Equations (College Board AP® Physics 1: Algebra-Based): Study Guide

Leander Oates

Written by: Leander Oates

Reviewed by: Caroline Carroll

Updated on

Kinematic equations

  • In physics, motion can be represented in a number of different ways:

    • Motion diagrams

    • Figures and data

    • Graphs

    • Equations

    • Narrative descriptions

  • For objects in a state of constant or uniform acceleration, there are three kinematic equations that can be used to describe their instantaneous linear motion in one dimension

    • Each of the three kinematics equations is listed on the equation sheet and will be provided in the exams

  • For all of these equations, the following conditions apply:

    • acceleration is uniform

      • therefore, average and instantaneous acceleration are equal

    • motion is along a straight line

      • motion is presented in the x direction but can also be applied to the y direction

  • For all these equations:

    • Time interval, t = t

      • The assumption is that the timer is started from zero, t0 = 0

    • Change in velocity, vx = vx  vx0

    • Displacement, x = x  x0

  • In exam questions, some of the information required for the calculation may be assumed

  • Phrases and situations to look out for:

    • The object begins at rest

      • The object is initially stationary; therefore, the initial velocity is zero

      • This leads to any expression containing initial velocity canceling to zero

    • Falling objects or objects in free fall

      • The acceleration is equal to the acceleration of free fall at Earth's surface, g = 10 m/s2

Kinematic equation 1

  • This equation is used when position and displacement are not required

vx = vx0 + axt

  • Where:

    • vx = final velocity in the x direction, measured in m/s

    • vx0 = initial velocity in the x direction, measured in m/s

    • ax = constant acceleration in the x direction, measured in m/s2

    • t = time interval, measured in s

Kinematic equation 2

  • This equation is used when final velocity is not required

x = x0 + vx0t + 12axt2

  • Where:

    • x = final position in the x direction, measured in m

    • x0 = initial position in the x direction, measured in m

    • vx0 = initial velocity in the x direction, measured in m/s

    • t = time interval, measured in s

    • ax = constant acceleration in the x direction, measured in m/s2

Kinematic equation 3

  • This equation is used when time is not required

vx2 = vx02 + 2ax(x  x0)

  • Where:

    • vx = final velocity in the x direction, measured in m/s

    • vx 0 = initial velocity in the x direction, measured in m/s

    • ax = constant acceleration in the x direction, measured in m/s2

    • x  x0 = displacement, measured in m

Other helpful equations in kinematics

  • Displacement can be calculated using velocity and time when acceleration is not required

x = 12(vx0 + vx)t

  • Where:

    • x = displacement, measured in m

    • vx0 = initial velocity in the x direction, measured in m/s

    • vx = final velocity in the x direction, measured in m/s

    • t = time interval, measured in s

  • Final position can be calculated when initial velocity is not required using the following equation:

x = x0 + vxt  12axt2

  • Where:

    • x = final position in the x direction, measured in m

    • x0 = initial position in the x direction, measured in m

    • vx = final velocity in the x direction, measured in m/s

    • t = time interval, measured in s

    • ax = constant acceleration in the x direction, measured in m/s2

Table of kinematics equations

Equation

Quantity not required

vx = vx0 + axt

(x  x0)

x = x0 + vx0t + 12axt2

vx

vx2 = vx02 + 2ax(x  x0)

t

x = 12(vx0 + vx)t

ax

x = x0 + vxt  12axt2

vx0

Examiner Tips and Tricks

It can be quicker to choose a kinematic equation based on the quantity that is not required for the calculation. The table above is a handy way to locate the relevant equation based on the quantity not required.

Worked Example

A rock is dropped from a bridge and strikes the water with an impact velocity of 18 m/s.

Calculate the height of the bridge.

Answer:

Step 1: Check for any implied quantities

  • The rock is dropped; this implies that the initial velocity is zero

  • The rock is in free fall; this implies that the acceleration is equal to the acceleration due to gravity at Earth's surface

Step 2: List the known quantities

  • Taking the positive direction to be downward

  • Initial velocity, vy0 = 0 m/s

  • Final velocity, vy = 18 m/s

  • Uniform acceleration, ay = 10 m/s2

Step 3: Choose the relevant kinematic equation

  • The question asks for the height of the bridge, which is equal to the displacement of the rock

  • The quantity not required in this calculation is time

vy2 = vy02 + 2ay(y  y0)

Step 4: Check if any of the quantities cancel to zero

  • Initial velocity is zero, therefore:

v2y = 0 + 2ay(y  y0)

v2y = 2ay(y  y0)

Step 5: Rearrange the equation

  • The question asks for displacement, so make (y  y0) the subject

(y  y0) = vy22ay

Step 6: Substitute in the known values to calculate

x = 1822 · 10

x = 16.2 m

Examiner Tips and Tricks

There is only one numerical value given in the question above; two of the values are implied. At first glance, it may seem like you don't have enough information to solve the problem. This should be seen as a clue that there is extra information hiding in the wording of the question, or that you may have already calculated a value in a previous question part.

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.