Angular Impulse (AQA A Level Physics): Revision Note

Exam code: 7408

Ashika

Author

Ashika

Last updated

Angular Impulse

  • In linear motion, the resultant force on a body can be defined as the rate of change of linear momentum:

F space equals space fraction numerator increment p over denominator increment t end fraction

  • This leads to the definition of linear impulse:

An average resultant force F acting for a time increment t produces a change in linear momentum increment p

increment p space equals space F increment t space equals space increment open parentheses m v close parentheses

  • Similarly, the resultant torque on a body can be defined as the rate of change of angular momentum:

tau space equals space fraction numerator increment L over denominator increment t end fraction

  • Where:

    • tau = resultant torque on a body (N m)

    • increment L = change in angular momentum (kg m2 s−1)

    • increment t = time interval (s)

  • This leads to the definition of angular impulse:

An average resultant torque tau acting for a time increment t produces a change in angular momentum increment L

increment L space equals space tau increment t space equals space increment open parentheses I omega close parentheses

  • Angular impulse is measured in kg m2 s−1, or N m s

  • This equation requires the use of a constant resultant torque

    • If the resultant torque changes, then an average of the values must be used

  • Angular impulse describes the effect of a torque acting over a time interval

    • This means a small torque acting over a long time has the same effect as a large torque acting over a short time

Angular Impulse on a Torque-Time Graph

  • The area under a torque-time graph is equal to the angular impulse or the change in angular momentum

    • This is because the area, angular impulse, is a fraction of the base × height, torque × time, increment L space equals space tau increment t

    • The fraction of torque × time depends upon the shape of the area under the graph

1-4-8--angular-impulse-on-a-torque-time-graph-ib-2025-physics

When the torque is not constant, the angular impulse is the area under a torque–time graph

Worked Example

The graph shows the variation of time t with the net torque tau on an object which has a moment of inertia of 6.0 kg m2.

1-4-8-angular-impulse-graph-worked-example-ib-2025-physics

At t = 0, the object rotates with an angular velocity of 2.0 rad s−1 clockwise.

Determine the magnitude and direction of rotation of the angular velocity at t = 5 s.

In this question, take anticlockwise as the positive direction.

Answer:

  • The area under a torque-time graph is equal to angular impulse, or the change in angular momentum

increment L space equals space tau cross times increment t

1-4-8-angular-impulse-graph-worked-example-ma-ib-2025-physics
  • The area under the positive curve (triangle) = 1 half cross times 10 cross times 3 space equals space 15 space straight N space straight m space straight s

  • The area under the negative curve (rectangle) = negative 5 cross times 2 space equals space minus 10 space straight N space straight m space straight s

  • Therefore, the overall change in angular momentum is

increment L space equals space 15 space minus space 10 space equals space 5 space straight N space straight m space straight s

  • The change in angular momentum is equal to

increment L space equals space increment open parentheses I omega close parentheses space equals space I open parentheses omega subscript f space minus space omega subscript i close parentheses

  • Where

    • Moment of inertia, I = 6.0 kg m2

    • Initial angular velocity, omega subscript i = −2.0 rad s−1 (clockwise is the negative direction)

  • Therefore, when t = 5 s, the angular velocity is

6 cross times open parentheses omega subscript f space minus space open parentheses negative 2 close parentheses close parentheses space equals space 5

6 omega subscript f space plus open parentheses 2 cross times 6 close parentheses space equals space 5

6 omega subscript f space equals space 5 space minus space 12

omega subscript f space equals space fraction numerator negative 7 over denominator 6 end fraction space equals space minus 1.17

Anti-clockwise is positive, so omega subscript f = 1.17 rad s−1 in the clockwise direction

Examiner Tips and Tricks

Many applications for angular impulse will be related to sports. These are similar to the linear impulse topic.

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.