Half-Life (AQA A Level Physics): Revision Note

Exam code: 7408

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Half-life

  • Half-life is defined as:

The average time taken for a given number of nuclei of a particular isotope to halve

  • Since activity A is proportional to the number of undecayed nuclei N, the activity of the sample will also halve

A decay curve of activity against time, with the activity halving after one half-life and halving again after two.
When a time equal to the half-life passes, the activity falls by half, when two half-lives pass, the activity falls by another half (which is a quarter of the initial value)
  • To find an expression for half-life, start with the equation for exponential decay:

N = N0 e−λt

  • Where:

    • N = number of nuclei remaining in a sample

    • N0 = the initial number of undecayed nuclei (when t = 0)

    • λ = decay constant (s-1)

    • t = time interval (s)

  • When time t is equal to the half-life t1/2, the activity N of the sample will be half of its original value, so N = 12N0

12N0 = N0 e−λt1/2

  • The formula can then be derived by first, dividing both sides by N0:

12 = e−λt1/2

  • Then, taking the natural log of both sides:

ln (12) = −λt1/2

  • Finally, applying properties of logarithms:

λt1/2 = ln 2

  • Therefore, half-life t1/2 can be calculated using the equation:

t1/2 = ln 2λ ≃ 0.693λ

  • This equation shows that half-life t1/2 and the radioactive decay rate constant λ are inversely proportional

    • Therefore, the shorter the half-life, the larger the decay constant and the faster the decay

Worked Example

Strontium-90 is a radioactive isotope with a half-life of 28.0 years. A sample of Strontium-90 has an activity of 6.4 × 109 Bq.

Calculate the decay constant λ, in s–1, of Strontium-90.

[2]

Answer:

Step 1: Convert the half-life into seconds

t1/2 = 28 years = 28 × (365 × 24 × 60 × 60) = 8.83 × 108 s [1 mark]

Step 2: Write the equation for half-life

t1/2 = ln 2λ

Step 3: Rearrange for λ and calculate

t1/2 = ln 28.83 × 108 = 7.85 × 10−10 s−1 (3 s.f.) [1 mark]

Examiner Tips and Tricks

Although you may not be expected to derive the half-life equation, make sure you're comfortable with how to use it in calculations such as that in the worked example.

Half-life from decay curves

  • The half-life of a radioactive substance can be determined from decay curves and log graphs

  • Since half-life is the time taken for the initial number of nuclei (or activity) to reduce by half, it can be found by:

    • drawing a line to the curve at the point where the activity has dropped to half of its original value

    • drawing a line from the curve to the time axis, this is the half-life

Log graphs

  • Straight-line graphs tend to be more useful than curves for interpreting data

    • Nuclei decay exponentially, therefore, to achieve a straight line plot, logarithms can be used

  • Take the exponential decay equation for the number of nuclei

N = N0 e−λt

  • Taking the natural logs of both sides

ln N = ln (N0) − λt

  • In this form, this equation can be compared to the equation of a straight line

y = mx + c

  • Where:

    • y-axis variable, y = ln N

    • x-axis variable, x = t

    • gradient, m = −λ

    • y-intercept, c = ln (N0)

  • Half-lives can be found in a similar way to the decay curve but the intervals will be regular as shown below:

A decay curve with the half-life read off at regular intervals. 100% halves to 50%, 25%, 12.5% and smaller values at each successive half-life.
A log graph of number of nuclei remaining against half-lives. A straight descending line from 100% at zero to 3.125% after five half-lives, halving at each integer half-life (50%, 25%, 12.5%, 6.25%).
Plotting ln(N) against time turns the exponential decay curve into a straight line with gradient −λ

Worked Example

The radioisotope technetium is used extensively in medicine. The graph below shows how the activity of a sample varies with time.

Decay curve of technetium activity against time. Time ranges from 0 to 24 hours and activity from 0 to 8 × 10⁷ Bq. The curve starts at 8 × 10⁷ Bq, halves every 6 hours, and reaches 0.5 × 10⁷ Bq at 24 hours.

Determine:

a) the decay constant for technetium [2]

b) the number of technetium atoms remaining in the sample after 24 hours [2]

Answer:

Part (a)

Step 1: Draw lines on the graph to determine the time it takes for technetium to drop to half of its original activity

Annotated decay curve of technetium activity against time. Time ranges from 0 to 24 hours and activity from 0 to 8 × 10⁷ Bq. The curve starts at 8 × 10⁷ Bq, halves every 6 hours, and reaches 0.5 × 10⁷ Bq at 24 hours. Activity falls from 8 × 10⁷ Bq to 4 × 10⁷ Bq (half the initial activity). Green lines mark ½A₀ = 4 and t₁/₂ = 6 hours.

Step 2: Read the half-life from the graph and convert to seconds

  • t1/2 = 6 hours = 6 × 60 × 60 = 21 600 s [1 mark]

Step 3: Write out the half life equation

t1/2 = ln 2λ

Step 4: Calculate the decay constant

λ = ln 2t1/2 = ln 221 600 = 3.21 × 10−5 s−1 [1 mark]

Part (b)

Step 1: Draw lines on the graph to determine the activity after 24 hours

Annotated decay curve of technetium activity against time. Time ranges from 0 to 24 hours and activity from 0 to 8 × 10⁷ Bq. The curve starts at 8 × 10⁷ Bq, halves every 6 hours, and reaches 0.5 × 10⁷ Bq at 24 hours. Annotated green lines show that at 24 hours the activity is 0.5 × 10⁷ Bq.
  • At t = 24 hours, A = 0.5 × 107 Bq [1 mark]

Step 2: Write out the activity equation

A = λN

Step 3: Calculate the number of atoms remaining in the sample

N = Aλ = 0.5 × 1073.21 × 10−5 = 1.56 × 1011 [1 mark]

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.