Half-Life (AQA A Level Physics): Revision Note

Exam code: 7408

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Half-Life

  • Half-life is defined as:

The average time taken for a given number of nuclei of a particular isotope to halve

  • Since activity A is proportional to the number of undecayed nuclei N, the activity of the sample will also halve

Half-life Graph, downloadable IGCSE & GCSE Physics revision notes

When a time equal to the half-life passes, the activity falls by half, when two half-lives pass, the activity falls by another half (which is a quarter of the initial value)

  • To find an expression for half-life, start with the equation for exponential decay:

N = N0 eλt

  • Where:

    • N = number of nuclei remaining in a sample

    • N0 = the initial number of undecayed nuclei (when t = 0)

    • λ = decay constant (s-1)

    • t = time interval (s)

  • When time t is equal to the half-life t1/2, the activity N of the sample will be half of its original value, so N = 12N0

12N0 = N0 eλt1/2

  • The formula can then be derived by first, dividing both sides by N0:

12 = eλt1/2

  • Then, taking the natural log of both sides:

ln (12) = λt1/2

  • Finally, applying properties of logarithms:

λt1/2 = ln 2

  • Therefore, half-life t1/2 can be calculated using the equation:

t1/2 = ln 2λ  0.693λ

  • This equation shows that half-life t1/2 and the radioactive decay rate constant λ are inversely proportional

    • Therefore, the shorter the half-life, the larger the decay constant and the faster the decay

Worked Example

Strontium-90 is a radioactive isotope with a half-life of 28.0 years. A sample of Strontium-90 has an activity of 6.4 × 109 Bq.

Calculate the decay constant λ, in s–1, of Strontium-90.

Answer:

Step 1: Convert the half-life into seconds

  • t1/2 = 28 years = 28 × (365 × 24 × 60 × 60) = 8.83 × 108 s

Step 2: Write the equation for half-life

t1/2 = ln 2λ

Step 3: Rearrange for λ and calculate

t1/2 = ln 28.83×108 = 7.85×1010 s1

Examiner Tips and Tricks

Although you may not be expected to derive the half-life equation, make sure you're comfortable with how to use it in calculations such as that in the worked example.

Half-Life from Decay Curves

  • The half-life of a radioactive substance can be determined from decay curves and log graphs

  • Since half-life is the time taken for the initial number of nuclei (or activity) to reduce by half, it can be found by

    • drawing a line to the curve at the point where the activity has dropped to half of its original value

    • drawing a line from the curve to the time axis, this is the half-life

Log Graphs

  • Straight-line graphs tend to be more useful than curves for interpreting data

    • Nuclei decay exponentially, therefore, to achieve a straight line plot, logarithms can be used

  • Take the exponential decay equation for the number of nuclei

N = N0 eλt

  • Taking the natural logs of both sides

ln N = ln (N0)  λt

  • In this form, this equation can be compared to the equation of a straight line

y = mx +c

  • Where:

    • y-axis variable, y = ln N

    • x-axis variable, x = t

    • gradient, m = λ

    • y-intercept, c = ln (N0)

  • Half-lives can be found in a similar way to the decay curve but the intervals will be regular as shown below:

Half Life Decay Curves 1, downloadable AS & A Level Physics revision notes
Half Life Decay Curves 2, downloadable AS & A Level Physics revision notes

Worked Example

The radioisotope technetium is used extensively in medicine. The graph below shows how the activity of a sample varies with time.

Worked Example - Half Life Curve, downloadable AS & A Level Physics revision notes

Determine:

a) The decay constant for technetium

b) The number of technetium atoms remaining in the sample after 24 hours

Answer:

Part (a)

Step 1: Draw lines on the graph to determine the time it takes for technetium to drop to half of its original activity

Worked Example - Half Life Curve Ans a, downloadable AS & A Level Physics revision notes

Step 2: Read the half-life from the graph and convert to seconds

  • t1/2 = 6 hours = 6 × 60 × 60 = 21 600 s

Step 3: Write out the half life equation

t1/2 = ln 2λ

Step 4: Calculate the decay constant

t1/2 = ln 221 600 = 3.2×105 s1

Part (b)

Step 1: Draw lines on the graph to determine the activity after 24 hours

Worked Example - Half Life Curve Ans b, downloadable AS & A Level Physics revision notes
  • At t = 24 hours, A = 0.5 × 107 Bq

Step 2: Write out the activity equation

A = λN

Step 3: Calculate the number of atoms remaining in the sample

N = Aλ = 0.5×1073.2×105 = 1.56×1011

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.