Required Practical: Investigating EMF & Internal Resistance (AQA A Level Physics): Revision Note
Exam code: 7408
Required practical: investigating EMF & internal resistance
Aims of the experiment
The overall aim of the experiment is to investigate the relationship between e.m.f and internal resistance by measuring the variation of current and voltage using a variable resistor
Independent variable = resistance, R (Ω)
Dependent variable = voltage, V (V) & current, I (A)
Control variables:
E.m.f of the cell
Internal resistance of the cell
Equipment list
Apparatus | Purpose |
|---|---|
1.5 V cell | To provide an e.m.f to the circuit |
Resistor | Unknown resistance – to act as internal resistance |
100 Ω variable resistor | To change the values of current and voltage in the circuit |
Voltmeter | 0–2 V range – to measure voltage |
Ammeter | 0–200 mA range – to measure current |
Wires | At least six leads – to make electrical connections |
Switch | To open between readings to not run down the battery |
Resolution of measuring equipment:
Voltmeter = 1 mV
Ammeter = 0.1 mA
Method

The cell and the resistor, labelled r, should be connected in series and considered to be a single cell.
With the switch open, record the reading V on the voltmeter.
Set the variable resistor to its maximum value, close the switch and record V and the reading I on the ammeter - make sure to open the switch between readings.
Vary the resistance of the variable resistor up to a minimum of eight to ten readings and record values for V and I for each resistance. Ensure to take readings for the whole range of the variable resistor.
An example of a suitable table might look like this:
1st reading | 2nd reading | 3rd reading | Mean | |||||
|---|---|---|---|---|---|---|---|---|
/ Ω | / V | / mA | / V | / mA | / V | / mA | / V | / mA |
0 | ||||||||
10 | ||||||||
20 | ||||||||
30 | ||||||||
40 | ||||||||
50 | ||||||||
60 | ||||||||
70 | ||||||||
80 | ||||||||
90 | ||||||||
100 | ||||||||
Analysing the results
The relationship between e.m.f. and internal resistance is given by
Where:
= electromotive force (V)
= current (A)
= resistance of the load in the circuit (Ω)
= internal resistance of the cell (Ω)
This can be simplified into the form:
Rearranging this equation for V:
Comparing this to the equation of a straight line:
(V)
(A)
Gradient = –r (Ω)
Y-intercept = (V)
Plot a graph of against and draw a line of best fit.
Measure the gradient of the graph and compare it with the manufacturer’s value of the resistor.
The y-intercept will be the e.m.f and the gradient will be the negative internal resistance:

Evaluating the experiment
Systematic Errors:
Only close the switch for as long as it takes to take each pair of readings
This will prevent the internal resistance of the battery or cell from changing during the experiment
Random Errors:
Only use fairly new cells otherwise the e.m.f. and internal resistance of run-down batteries can vary during the experiment
Wait for the reading on the voltmeter and ammeter to stabilise (stop fluctuating) before recording the values
Take multiple repeat readings (at least three) for each voltage and current and calculate a mean to reduce random errors
Safety considerations
This is a very safe experiment, however, electrical components can get hot when used for a long period
Switch off the power supply right away if there is a smell of burning
Make sure there are no liquids close to the equipment, as this could damage the electrical equipment
Worked Example
In an experiment, a student uses a variable resistor as an external load. The current flowing through the circuit is measured with a suitable milliammeter and the potential difference across the variable resistor is measured with a voltmeter for a range of resistance values. The data collected was as follows:
/ V | / mA |
|---|---|
1.60 | 0 |
1.30 | 13.1 |
1.14 | 20.0 |
0.96 | 28.2 |
0.80 | 35.2 |
0.65 | 41.5 |
0.49 | 48.8 |
0.38 | 53.4 |
0.23 | 60.3 |
0.10 | 66.0 |
Plot a graph of these results and determine the e.m.f. and the internal resistance directly from the graph.
[4]
Answer:
Step 1: Plot the data on a graph of V against I and draw a line of best fit

[1 mark]
Step 2: Draw the largest triangle possible in order to calculate the gradient

[1 mark]
Step 3: Determine the e.m.f. and the internal resistance from the graph
From this equation:
Gradient = –r (Ω)
Y-intercept = (V)
Therefore:
Internal resistance, r = 22.7 Ω [1 mark]
E.m.f. = 1.60 V [1 mark]
Unlock more, it's free!
Was this revision note helpful?
Build on this topic