Centripetal Force (AQA A Level Physics): Revision Note

Exam code: 7408

Katie M

Written by: Katie M

Reviewed by: Tim

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Calculating centripetal force

  • An object moving in a circle is not in equilibrium, it has a resultant force acting upon it

    • This is known as the centripetal force and is what keeps the object moving in a circle

  • The centripetal force (F) is defined as:

    The resultant force towards the centre of the circle required to keep a body in uniform circular motion.

  • It is always directed towards the centre of the body's rotation

  •  Centripetal force can be calculated using:

F = mv2r = mrω2 = mvω

  • Where:

    • F = centripetal force (N)

    • m = mass (kg)

    • v = linear velocity (m s-1)

    • ω = angular speed (rad s-1)

    • r = radius of the orbit (m)

A point on a circular orbit has linear speed v tangential to the circle, angular speed omega shown by an anticlockwise curved arrow, radius r to the centre, and centripetal force F directed inward.
Centripetal force is always perpendicular to the direction of travel
  • Note: centripetal force and centripetal acceleration act in the same direction

    • This is due to Newton’s second law

  • The centripetal force is not a separate force of its own

    • It can be any type of force, depending on the situation, which keeps an object moving in a circular path

Situation

Centripetal force

Car travelling around a roundabout

Friction between car tyres and the road

Ball attached to a rope moving in a circle

Tension in the rope

Earth orbiting the Sun

Gravitational force

  • When solving circular motion problems involving one of these forces, the equation for centripetal force can be equated to the relevant force equation

  • For example, for a mass orbiting a planet in a circular path, the centripetal force is provided by the gravitational force

  • When an object travels in circular motion, there is no work done

    • This is because there is no change in kinetic energy

Worked Example

A 300 g ball is made to travel in a circle of radius 0.8 m on the end of a string. If the maximum force the ball can withstand before breaking is 60 N, what is the maximum speed of the ball?

[2]

Answer:

Step 1: List the known quantities

  • Mass, m = 300 g = 300 × 10-3 kg

  • Radius, r = 0.8 m

  • Resultant force, F = 60 N

Step 2: Rearrange the centripetal force equation for v

Fmax = mv2maxr

vmax =rFmaxm [1 mark]

Step 3: Substitute in the values

vmax= 0.8 × 60300 × 10−3 = 12.6 m s−1 [1 mark]

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.