Angular Speed (AQA A Level Physics): Revision Note

Exam code: 7408

Richard Boole

Written by: Richard Boole

Reviewed by: Timothy Sit

Updated on

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Angular speed

  • Any object travelling in a uniform circular motion at the same speed travels with a constantly changing velocity

  • This is because it is constantly changing direction, and is therefore accelerating

  • The angular speed (⍵) of a body in circular motion is defined as:

    The rate of change in angular displacement with respect to time

  • Angular speed is a scalar quantity and is measured in rad s-1

  • It can be calculated using:

ω = ∆θ∆t

  • Where:

    • ω = angular speed (rad s-1)

    • ∆θ = change in angular displacement (radians)

    • ∆t = time interval (s)

A circular-motion diagram shows radius r from the centre to a point on the circumference, angular displacement delta theta at the centre, angular speed omega around the circle, and linear speed v tangentially upwards.
When an object is in uniform circular motion, velocity constantly changes direction, but the speed stays the same
  • Taking the angular displacement of a complete cycle as 2π, the angular speed ω can be calculated using the equation:

ω = vr = 2πf = 2πT

  • Where:

    • v = linear speed (m s-1)

    • r = radius of orbit (m)

    • f = frequency (Hz)

    • T = time period (s)

  • Angular velocity is the same as angular speed, but it is a vector quantity

  • This equation shows that:

    • The greater the rotation angle θ in a given amount of time, the greater the angular velocity ⍵

    • An object rotating further from the centre of the circle (larger r) moves with a smaller angular velocity (smaller ⍵)

Worked Example

A bird flies in a horizontal circle with an angular speed of 5.25 rad s−1 of radius 650 m.

Calculate:

a) The linear speed of the bird [2]

b) The frequency of the bird flying in a complete circle [2]

Answer:

Part (a)

  • Use the angular speed equation to calculate the linear speed

ω = vr

v = ωr = 650 × 5.25 [1 mark]

v = 3410 m s−1 (3 s.f.) [1 mark]

Part (b)

  • Use the angular speed equation to calculate the frequency

ω = 2πf

f = ω2π = 5.252π [1 mark]

f = 0.836 Hz (3 s.f.) [1 mark]

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Richard Boole

Author: Richard Boole

Expertise: Curriculum Expert

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.

Timothy Sit

Reviewer: Timothy Sit

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.