p–V Diagrams (AQA A Level Physics): Revision Note

Exam code: 7408

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p–V diagrams

  • When a gas expands, it does work on its surroundings by exerting pressure on the walls of the container it's in

  • For a gas inside a piston, the force exerted by the gas pushes the piston outwards

    • As a result, work is done by the gas when the piston expands the volume of the gas

  • Alternatively, if an external force is applied to the piston, the gas will be compressed

    • In this case, work is done on the gas when the piston compresses the gas

A gas at pressure p pushes a piston through distance s. The piston has cross-sectional area A, and the expanded gas volume is labelled V = A × s. The force exerted by the gas is shown by an arrow.
The expansion of the gas does work on the piston by exerting a force over a distance, s
  • The work done when the volume of a gas changes at constant pressure is:

W = p∆V

  • Where:

    • W = work done (J)

    • p = pressure of the gas (Pa)

    • ∆V = change in the volume of the gas (m3)

  • This equation assumes that the surrounding pressure does not change as the gas expands

    • This is true if the gas is expanding against the pressure of the atmosphere, which changes very slowly

p-V diagrams

  • Pressure-volume (p-V) diagrams are often used to represent changes in the state of a gas in thermodynamic processes

A gas is compressed by a moveable piston, resulting in a negative volume change and work is done on the gas. A gas is expanded by a moveable piston, resulting in a positive volume change and work is done by the gas.
Positive or negative work done depends on whether the gas is compressed or expanded
  • The area under a p-V diagram is equal to the work done

  • When a gas expands (at constant pressure), work done is positive

    • Volume increases +∆V

    • Work is done by the gas +W

A p–V diagram shows a blue horizontal line pointing right which indicates gas expansion at constant pressure. A positive volume change plus delta V is shown. The shaded rectangular area represents positive work done by the gas, plus W.
The work done by an expanding gas at constant pressure is positive
  • When a gas is compressed (at constant pressure), work done is negative

    • Volume decreases −∆V

    • Work is done on the gas −W

A p–V diagram shows a blue horizontal line pointing left which indicates gas compression at constant pressure. A negative volume change minus delta V is shown. The shaded rectangular area represents negative work done on the gas, minus W.
The work done on a compressing gas at constant pressure is negative
  • When both the volume and pressure of gas changes, the work done can be determined from the area under a p-V diagram

A p-V diagram shows a curved blue line with an arrow pointing right sloping downward from a high-pressure, low-volume point to a lower-pressure, higher-volume point. The shaded area beneath the curve represents work done by the gas, plus W.
The work done by an expanding gas with a decreasing pressure is positive
  • In the context of engines, these are referred to as indicator diagrams

Worked Example

When a balloon is inflated, its rubber walls push against the air around it.

Calculate the work done when the balloon is blown up from 0.015 m3 to 0.030 m3.

Atmospheric pressure = 1.0 × 105 Pa.

[2]

Answer:

  • The work done by a gas is equal to

W = p∆V

  • Where the change in volume is

∆V = final volume − initial volume

∆V = 0.030 − 0.015 = 0.015 m3 [1 mark]

  • Therefore, work done is

W = (1.0 × 105) × 0.015 = 1500 J [1 mark]

Worked Example

An ideal gas is compressed, as shown on the graph below. 

A p–V graph shows a straight line pointing from 600 cm³ at 300 kPa to 200 cm³ at 900 kPa.

(a) For this change, state and explain whether work is done on the gas or by the gas [2]

(b) Determine the value of the work done and state whether it is positive or negative [3]

Answer:

Part (a)

  • The volume decreases so the gas is compressed [1 mark]

  • Therefore, work is done on the gas [1 mark]

Part (b)

  • The work done is equal to the area under the p-V diagram

A p–V graph shows a straight line pointing from 600 cm³ at 300 kPa to 200 cm³ at 900 kPa. The shaded area underneath the line is split into a triangle and rectangle. Labels calculate 120 J + 120 J for both areas.

W = 12(600 × 103)(400 × 10−6) + (300 × 103)(400 × 10−6) [1 mark]

 W = 120 + 120 = 240 J [1 mark]

  • The gas is compressed, so work done on the gas is negative, W = −240 J [1 mark]

Examiner Tips and Tricks

You need to be able to interpret p-V diagrams, and you might also be asked to link them to the ideal gas equation, pV = nRT or pVT = constant.

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Timothy Sit

Reviewer: Timothy Sit

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.