The Decibel Scale (AQA A Level Physics): Revision Note

Exam code: 7408

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Relative Intensity Levels of Sound

  • When the sound waves enter the auditory canal, a stationary wave is set up

    • This can be modelled as a tube with an antinode forming at the open end and a node forming at the closed end

  • As a result, the auditory canal acts as a closed tube resonator which enhances the sensitivity of sounds in specific ranges

    • In the case of human hearing, this is what enables us to hear sounds in the range of 20 Hz to 20,000 Hz

    • The highest sensitivity region is around 2 to 5 kHz, which corresponds to frequencies of speech

Resonance in the Auditory Canal

10-2-2-auditory-canal-resonance

The auditory canal works as a closed tube resonator which is sensitive to specific ranges of frequencies

The Decibel Scale

  • The ear’s ability to detect small changes in sound intensity is referred to as its sensitivity

    • This is measured in decibels (dB)

  • The sensitivity of human hearing depends on the frequency of the sound

  • The graph of sound intensity and frequency shows that the ear is most sensitive to sounds with a frequency of about 3000 Hz

The Relationship between Sound Intensity and Frequency 

10-2-2-intensity-frequency-response-of-hearing

The human ear is most sensitive to sounds with a frequency of around 3000 Hz 

  • For frequencies much greater, or lower than 3000 Hz, the intensity of sound must be several orders of magnitude higher to be detected

    • This large range of intensities shows that the response of the ear is logarithmic

  • The decibel (dB) scale is also logarithmic 

    • Hence, the decibel scale is a useful way of measuring the response of the human ear to changes in sound intensity

The Decibel Scale

4s3YS9OO_10-2-2-the-decibel-scale

The decibel scale is used to represent the large range of intensities that the ear can detect on a logarithmic scale

Worked Example

Give two reasons why logarithmic scales are used to measure the loudness of a sound.

Answer:

  • The ear can detect sounds over a very large range of intensities, across many orders of magnitude

  • This means the ear’s perception of loudness is logarithmic

  • Therefore, a logarithmic scale is a useful way to plot or analyse such a large range of numbers

  • For example, on the graph above:

    • The range of frequency of human hearing is ~20 to 20 000 Hz

    • So, frequency values are plotted on the axes in increments of 10 (1, 10, 100, 1000, etc)

    • In this range of frequencies, intensity values range from 10−12 to 102 W m−2

    • So, intensity value are plotted on the axes in increments of 100 (10−12, 10−10, 10−8, 10−6, etc)

Loudness & Decibels

  • Intensity of a sound wave is defined as:

    The amount of sound energy that passes a point per second per unit area

  • Intensity can be described by the equation:

I = PA

  • Where

    • I = intensity of sound wave (W m−2)

    • P = power, or energy transferred per second (W)

    • A = area through which sound waves pass (m2)

  • For a sound wave that spreads out uniformly in all directions, it can be assumed to propagate as a spherical shell

    • The surface area of a sphere is 4πr2

    • The radius r of this sphere is equal to the distance between the source of the sound and the receiver

  • This means the intensity of the sound spreads out according to an inverse square law

I = P4πr2

Inverse Square Law of Sound Intensity

10-2-2-inverse-square-law-of-sound-intensity

When the source of the sound is twice as far away, it has spread over four times the area, hence the intensity is four times smaller

  • The human ear can detect and respond to a very large range of intensities

  • The response of the ear to changes in sound intensity, or the perceived change in loudness, is directly proportional to the logarithm of the percentage change in intensity

perceived change in loudness  log (I2I1)

  • Where

    • I1 = initial intensity of sound wave (W m−2)

    • I2 = final intensity of sound wave (W m−2)

  • This is known as the logarithmic response of sound intensity

    • This means when the intensity of a sound doubles, and doubles again the loudness increases in fixed steps (for a given frequency)

    • For example, an increase in sound intensity from 1 × 10−12 W m−2 to 2 × 10−12 W m−2 is perceived to be the same change in loudness as 1 W m−2 to 2 W m−2

  • The threshold of hearing I0 is defined as:

    The lowest intensity that a normal human ear can detect at a frequency of 1 kHz

  • This is equal to about 1 × 10−12 W m−2

  • The intensity level of a sound can be defined as

intensity level = 10 log (II0)

  • Where:

    • Intensity level is measured in decibels (dB)

    • I = intensity of the sound wave (W m−2)

    • I0 = threshold of hearing intensity = 1 × 10−12 W m−2

  • The threshold of hearing is assigned a sound level of 0 decibels, or 0 dB

    • An intensity level of 10 dB is 10 times louder than I0, or 1 × 10−11 W m−2

    • An intensity level of 20 dB is 100 times louder than I0, or 1 × 10−10 W m−2

    • An intensity level of 30 dB is 1000 times louder than I0, or 1 × 10−9 W m−2

Worked Example

Person A hears a sound of intensity level 95 dB. Person B hears the same sound at an intensity level of 82 dB whilst standing 20 m away from the source of the sound.

Calculate how far away person A is from the source of the sound.

Answer:

Step 1: Convert the intensity levels in dB into intensities

intensity level = 10 log (II0)

  • Intensity level of person A = 10 log (IAI0) = 95 dB

log (IAI0) = 9510 = 9.5

  • Take logs of both sides:

IAI0 = 109.5      IA = I0 × 109.5

  • Intensity level of person B = 10 log (IBI0) = 82 dB

log (IBI0) = 8210 = 8.2

  • Take logs of both sides:

IBI0 = 108.2      IB = I0 × 108.2

Step 2: Use the inverse square law of intensity to find the ratio of IA and IB

  • Intensity of a sound wave:

I = PA = P4πr2

  • Since the source of the sound is the same, the value of power P is the same, so I  1r2

IAIB = (rBrA)2

Step 3: Rearrange and substitute values to find rA

rBrA = IAIB

rA = rBIAIB      rA = rB IBIA

rA = 20 × 108.2109.5 = 4.5 m

  • Hence, person A is standing 4.5 m from the source of the sound

Worked Example

On the ground near an airport, the intensity level of an aircraft taking off is measured to be 120 dB.

Determine the intensity level, in dB, due to two aircraft taking off at the same time.

Threshold of hearing, I0 = 1.0 × 1012 W m2

Answer:

Step 1: Convert the intensity level in dB into intensity

intensity level (dB) = 10 log (II0)

  • Intensity level due to each aircraft = 120 dB

10 log (II0) = 120          log (II0) = 12

  • Take logs of both sides:

II0 = 1012          I = 1012I0

  • Note: This is equivalent to I = (1012)×(1.0×1012) = 1.0 W m2, but it is simpler to keep in terms of I0 

Step 2: Add the intensities together to obtain the total intensity

  • Intensity due to both aircraft:

I = 1012I0 +1012I0 = 2×1012I0

Step 3: Convert the intensity back into dB using the intensity level equation

intensity level (dB) = 10 log (2×1012I0I0) = 10 log (2×1012)

intensity level due to both aircraft = 123 dB

Examiner Tips and Tricks

For two or more sounds, intensity levels in decibels cannot be added together to obtain a total intensity level, as this is not how logarithmic scales work. Remember to convert the values in decibels into intensities in W m−2, then you can add them together and convert back into decibels to obtain the intensity level of the combined sound waves.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.