Stress & Strain (AQA A Level Physics): Revision Note

Exam code: 7408

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Reviewed by: Tim

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Tensile stress & strain

  • Opposite forces can deform an object

  • If the forces stretch the object, then they are tensile forces

  • Tensile forces lead to the two properties of materials known as tensile stress and tensile strain

Tensile stress

  • Tensile stress is defined as the force exerted per unit cross-sectional area of a material

σ = FA

  • Where:

    • σ = tensile stress (Pa)

    • F = force applied (N)

    • A = cross-sectional area (m2)

  • The ultimate tensile stress is the maximum force per original cross-sectional area a wire is able to support until it breaks

  • σ is the Greek letter lower-case 'sigma'

  • σ has the units of pascals (Pa), which is the same units as pressure (also force ÷ area)

Tensile strain

  • Strain is the extension per unit length

  • This is a deformation of a solid due to stress in the form of elongation or contraction

Tensile strain = ∆LL

  • Where:

    • ∆L = extension (m)

    • L = original length (m)

  • The strain is a dimensionless unit because it’s the ratio of lengths

  • Sometimes strain might be written as a percentage

    • For example, extending a 0.1 m wire by 0.005 m would produce a strain of (0.005 ÷ 0.1) × 100 = 5 %

Worked Example

A brass wire of length 4.50 m and a radius of 0.2 mm is extended to a total length of 4.53 m when a tensile force of 50 N is applied.

Calculate for the brass wire:

(i) The tensile stress [2]

(ii) The tensile strain [2]

Answer:

Part (i)

Step 1: Write down the tensile stress equation

σ = FA

Step 2: Calculate the cross-sectional area, A of the wire

  • A wire has a circular cross-sectional area = πr2

A = π × (0.2 × 10−3)2 = 1.2566 × 10−7 m2 [1 mark]

Step 3: Substitute values in the tensile stress equation

σ = FA = 501.2566 × 10−7 = 3.98 × 108 Pa [1 mark]

Part (ii)

Step 1: Write down the tensile strain equation

Tensile strain = ∆LL

Step 2: Determine the extension

  • The extension is total length – the original length

Extension = 4.53 – 4.50 = 0.03 m [1 mark]

Step 3: Substitute values in the tensile strain equation

Tensile strain = 0.034.50 = 6.7 × 10−3 [1 mark]

Examiner Tips and Tricks

Since strain is a ratio, you don't have to convert the extension and original length into metres. As long as they both have the same units, your strain will be correct.

Stress-strain curves

  • Stress-strain curves describe the properties of materials such as whether they are brittle, ductile and up to what stress and strain they obey Hooke's Law and have elastic and / or plastic behaviour

  • Each material will have a unique stress-strain curve

Stress–strain graph comparing different materials where stress axis is between 0–1000 MPa and strain axis is between 0–0.2. Ceramic and high-carbon steel reach high stress at low strain. Glass reaches 500 MPa stress at 0.075 strain. Copper extends to 0.2 at about 300 MPa.
Each material has its own stress-strain curve up to its breaking stress
  • There are important points on the stress-strain graph, some are similar to the force-extension graph

Annotated stress–strain graph with stress in pascals against strain. It labels the limit of proportionality, elastic limit, yield stress and breaking point. Hooke’s law, elastic and plastic regions, and energy stored per unit volume are indicated.
Key points on a stress-strain graph mark where a material stops behaving elastically and where it breaks
  • The key points that are unique to the stress-strain graph are:

    • Yield Stress: The force per unit area at which the material extends plastically for no / a small increase in stress

    • The elastic strain energy stored per unit volume is the area under the Hooke's Law (straight line) region of the graph

    • Breaking point: The stress at this point is the breaking stress

      • This is the maximum stress a material can stand before it fractures

    • Elastic region: The region of the graph up till the elastic limit

      • In this region, the material will return to its original shape when the applied force is removed

    • Plastic region: The region of the graph after the elastic limit

      • In this region, the material has deformed permanently and will not return to its original shape when the applied force is removed

Worked Example

The graph below shows a stress-strain curve for a copper wire.

Stress–strain where stress ranges from 0–200 × 10⁶ pascals and strain from 0–6 × 10⁻³. The curve bends near 130 × 10⁶ pascals and ends at a cross near 190 × 10⁶ pascals.

From the graph state the value of:

(i) The breaking stress [1]

(ii) The stress at which plastic deformation begins [1]

Answer:

Part (i)

Step 1: Define breaking stress

  • The breaking stress is the maximum stress a material can stand before it fractures

  • This is the stress at the final point on the graph

Step 2: Determine breaking stress from the graph

  • Draw a line to the y axis at the point of fracture

Stress–strain where stress ranges from 0–200 × 10⁶ pascals and strain from 0–6 × 10⁻³. The curve bends near 130 × 10⁶ pascals and ends at a cross near 190 × 10⁶ pascals. A line is drawn across from the fracture point to the stress axis giving 190 × 10⁶ pascals.
  • Therefore, the breaking stress is 190 MPa [1 mark]

Part (ii)

Step 1: Define plastic deformation

  • Plastic deformation is when the material is deformed permanently and will not return to its original shape once the applied force is removed

  • This is shown on the graph where it is curved

Step 2: Determine the stress of where plastic deformation begins on the graph

  • Draw a line to the y axis at the point where the graph starts to curve

Stress–strain where stress ranges from 0–200 × 10⁶ pascals and strain from 0–6 × 10⁻³. The curve bends near 130 × 10⁶ pascals and ends at a cross near 190 × 10⁶ pascals. A line is drawn across from where the curve begins to the stress axis giving 130 × 10⁶ pascals.
  • Therefore, plastic deformation begins at a stress of 130 MPa [1 mark]

Examiner Tips and Tricks

When you read a value off a graph where the reading is subjective, the mark scheme usually accepts a range. In the graph above, you would get the mark for any value from 120 MPa to 135 MPa for where the graph starts to curve.

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Ashika

Author: Ashika

Expertise: Physics Content Creator

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.