The Diffraction Grating (AQA A Level Physics): Revision Note

Exam code: 7408

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The diffraction grating

  • A diffraction grating is a piece of optical equipment that also creates a diffraction pattern when it diffracts:

    • monochromatic light into bright and dark fringes

    • white light into its different wavelength components

A pink laser beam passes through a mounted diffraction grating, producing many separated beams that fan out at different angles to the right.
A laser light is diffracted using a diffraction grating
  • A diffraction grating consists of a large number of very thin, equally spaced parallel slits carved into a glass plate

A glass plate containing many parallel vertical grooves cut at regular spacings, labelled spacing d.
A diffraction grating consists of many parallel, equally spaced slits cut into the glass plate

The diffraction grating equation

  • Diffraction gratings are useful because they create a sharper pattern than a double slit

    • This means their bright fringes are narrower and brighter while their dark regions are wider and darker

Monochromatic light from a laser passes through a diffraction grating and forms a row of separated bright fringes on a screen.
A diffraction grating is used to produce narrow bright fringes when laser light is diffracted through it
  • Just like for single slit diffraction and double-slit interference, the regions where constructive interference occurs are also the regions of maximum intensity

  • Their location can be calculated using the diffraction grating equation

d sinθ = nλ

  • Where:

    • d is the distance between the slits on the grating (m)

    • θ is the angle of diffraction of the light of order n from the normal as it leaves the diffraction grating (°)

    • n is the order of the maxima, the number of the maxima away from the central (n = 0)

    • λ is the wavelength of the light from the source (m)

Slit spacing

  • Diffraction gratings come in different sizes

    • The sizes are determined by the number of lines per millimetre (lines / mm) or lines per m

    • This is represented by the symbol N

  • d can be calculated from N using the equation:

d = 1N

  • If N is given in terms of lines per mm then d will be in mm

  • If N is given in terms of lines per m then d will be in m

An educational diffraction grating shows three sections labelled 100, 300 and 600 lines per millimetre.
Diffraction gratings come in different sizes according to the number of lines per mm

Angular separation

  • The angular separation of each maxima is calculated by rearranging the grating equation to make θ the subject

  • The angle θ is taken from the centre meaning the higher orders of n are at greater angles

Diagram showing points of constructive interference at diffraction orders n = 0, ±1 and ±2. The angles from the central maximum are labelled θ₁ for first order and θ₂ for second order, with θ₂ larger.
Angular separation increases as the order of maxima increases
  • The angular separation between two angles is found by subtracting the smaller angle from the larger one

  • The angular separation between the first and second maxima at n1 and n2 is θ2 − θ1

Orders of maxima

  • The maximum angle of diffraction with which maxima can be seen is when the beam is at right angles to the diffraction grating

    • This means θ = 90° and sinθ = 1

  • The highest order of maxima visible is therefore calculated by the equation:

n = dλ

  • Since n is an integer number of maxima, if the value obtained is a decimal it must be rounded down to determine the highest-order visible

    • E.g If n is calculated as 2.7 then n = 2 is the highest-order visible

Worked Example

An experiment was set up to investigate light passing through a diffraction grating with a slit spacing of 1.7 µm. The fringe pattern was observed on a screen. The wavelength of the light is 550 nm.

Light of wavelength lambda enters from the left and hits a diffraction grating. A screen shows the central maximum and second-order lines above and below. Alpha is the angle between the two second order lines, beta is the angle from the central maximum to the upper second order line.

Calculate the angle α between the two second-order lines.

[3]

Answer:

Step 1: List the known quantities

  • Slit spacing, d = 1.7 μm = 1.7 × 10−6 m

  • n = 2 for the second order line

  • Wavelength of light, λ = 550 nm = 550 × 10−9 m

Step 2: Calculate the angle from the central maximum to the second order line

d sinθ = nλ

sinθ = nλd = 2 × (550 ×10−9)1.7 × 10−6 = 0.6471 [1 mark]

θ = sin−1(0.6471) = 40.32° [1 mark]

Step 3: Calculate α

  • θ is the angle from the central maximum to the second order line, so

α = 2θ = 2 × 40.32 = 80.64° = 81° (2 s.f.) [1 mark]

Examiner Tips and Tricks

Take care that the angle θ is the correct angle taken from the centre and not the angle taken between two orders of maxima.

Derivation of the diffraction grating equation

  • When light passes through the slits of the diffraction grating, the path difference at the zeroth-order maximum is zero

  • At the first order maxima, there is constructive interference, hence the path difference is λ

  • Therefore, at the nth order maxima, the path difference is equal to nλ

Parallel red rays leave two points separated by d at angle theta to the horizontal normal, with path difference lambda. A right triangle shows d, lambda and theta; sine theta equals lambda divided by d.
Using this diagram and trigonometry, the diffraction grating equation can be derived
  • Using trigonometry, an expression for the first-order maxima can be written:

sin θ = λd

  • Where:

    • θ= the angle between the normal and the maxima

    • λ = the wavelength of the light (m)

    • d = the slit separation (m)

  • This means, for n = 1:

sin θ1 = λd

  • Similarly, for n = 2, where the path difference is 2λ:

sin θ2 = 2λd

  • Therefore, in general, where the path difference is nλ:

sin θn = nλd

  • A small rearrangement leads to the equation for the diffraction grating:

d sin θ = nλ

Applications of diffraction gratings

  • Diffraction gratings are useful for separating light of different wavelengths with high resolution

  • They are used in spectrometers to:

    • analyse light from stars

    • analyse the composition of a star

    • chemical analysis

    • measure red shift / rotation of stars

    • measure the wavelength / frequency of light from a star

    • observe the spectra of materials

    • analyse the absorption / emission spectra in stars

  • Diffraction gratings also play a role in X-ray crystallography:

    • X-rays are directed at a thin crystal sheet which acts as a diffraction grating to form a diffraction pattern

    • This is because the wavelength of X-rays is similar in size to the gaps between the atoms

    • This diffraction pattern can be used to measure the atomic spacing in certain materials

  • Diffraction gratings are also used in monochromators:

    • To specifically analyse a wavelength emitted by molecules in diseased cells from a biopsy sample

    • To help excite molecules in a sample with a specific wavelength of light

  • Diffraction gratings are used to select the optimum wavelength of light for use in an optical fibre

Halogen light passes through a labelled sample and diffraction grating, separating wavelengths into coloured rays to form an absorption spectrum with dark lines.
Diffraction gratings are most commonly used in spectrometers. These devices play a crucial role in areas of physics such as atomic physics and astrophysics

Examiner Tips and Tricks

Note that while you will be expected to know some applications of diffraction gratings, you will not be tested on specific apparatus or techniques such as spectrometry. When describing the use of spectrometers, avoid using vague terms such as 'observe spectra’, ‘spectroscopy’, ‘view absorption / emission spectrum’, ‘compare spectra’, ‘look at light from stars’.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.