The Arrhenius Equation (College Board AP® Chemistry): Study Guide
The Arrhenius Equation
The effect of temperature on reaction rate can be explained in terms of kinetic theory
Increasing temperature greatly increases the fraction of molecules with very high velocity and high kinetic energies
These molecules are more likely to have energy equal to or greater than the activation energy when they collide, so a greater proportion of collisions reach the transition state and react
Hence, the higher the temperature, the larger the fraction of molecules that can provide the activation energy required for reaction
The collision model gives the rate constant for an elementary reaction as
k = p × Z × f (equation 1)
Where:
Z, the collision frequency
f, the fraction of collisions with energy equal to or greater than the activation energy
p, the steric factor (the fraction of collisions with a suitable orientation)
The steric factor, p, does not depend on temperature
The collision frequency, Z, is relatively insensitive to temperature
For example, when the temperature increases from 500 to 600 K, Z increases by less than 10%
On the other hand, the relationship between the fraction of collisions with energy greater than the activation energy and temperature has been shown as
f = e-Ea/RT (equation 2)
Where:
e is a mathematical constant with an approximate value of 2.718
Ea is the activation energy, in J/mol
R is the gas constant, 8.314 J mol-1 K-1
T is the absolute temperature in K
A combination of equations 1 and 2 gives the Arrhenius equation, which shows how the rate constant is dependent on temperature
k = Ae-Ea/RT
Where A is a constant and called the frequency factor
This factor is related to the frequency of collisions,* Z* and the steric factor, p
In general, as the value of Ea increases, k decreases
This is because the fraction of molecules that possess the required energy is smaller
On taking the natural log of both sides of the Arrhenius equation, the equation becomes:
ln k = ln A - Ea/RT
A plot of ln k against 1/T gives a straight line with a negative slope:
The Arrhenius plot

slope = -Ea/R
y-intercept = ln A
A larger activation energy gives a steeper line
Examiner Tips and Tricks
Calculations involving the Arrhenius equation are not assessed on the AP Exam. You do need the qualitative relationships: a higher activation energy gives a smaller k, and a higher temperature gives a larger k because a greater fraction of collisions have energy equal to or greater than Ea. Raising the temperature does not change Ea itself
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