The Arrhenius Equation (College Board AP® Chemistry): Study Guide

Oluwapelumi Kolawole

Written by: Oluwapelumi Kolawole

Reviewed by: Stewart Hird

Updated on

The Arrhenius Equation

  • The effect of temperature on reaction rate can be explained in terms of kinetic theory

    • Increasing temperature greatly increases the fraction of molecules with very high velocity and high kinetic energies

    • These molecules are more likely to have energy equal to or greater than the activation energy when they collide, so a greater proportion of collisions reach the transition state and react

    • Hence, the higher the temperature, the larger the fraction of molecules that can provide the activation energy required for reaction

  • The collision model gives the rate constant for an elementary reaction as

k = p × Z  ×  f            (equation 1)

  • Where:

    • Z, the collision frequency

    • f, the fraction of collisions with energy equal to or greater than the activation energy

    • p, the steric factor (the fraction of collisions with a suitable orientation)

  • The steric factor, p, does not depend on temperature

  • The collision frequency, Z, is relatively insensitive to temperature

    • For example, when the temperature increases from 500 to 600 K, Z increases by less than 10%

  • On the other hand, the relationship between the fraction of collisions with energy greater than the activation energy and temperature has been shown as

f = e-Ea/RT                   (equation 2)

  • Where:

    • e is a mathematical constant with an approximate value of 2.718

    • Ea is the activation energy, in J/mol

    • R is the gas constant, 8.314 J mol-1 K-1

    • T is the absolute temperature in K

  • A combination of equations 1 and 2 gives the Arrhenius equation, which shows how the rate constant is dependent on temperature

k = Ae-Ea/RT

  • Where A is a constant and called the frequency factor

  • This factor is related to the frequency of collisions,* Z* and the steric factor, p

  • In general, as the value of Ea increases, k decreases

    • This is because the fraction of molecules that possess the required energy is smaller

  • On taking the natural log of both sides of the Arrhenius equation, the equation becomes:

ln k = ln A - Ea/RT

  • A plot of ln k against 1/T gives a straight line with a negative slope:

The Arrhenius plot

Arrhenius plot with ln k on the vertical axis against 1/T in K⁻¹ on the horizontal axis; a red line of best fit slopes downwards, with gradient equals minus Eₐ divided by R and intercept equals ln A.
A plot of ln k against 1/T is a straight line with slope −E~a~/R, so a larger activation energy gives a steeper line
  • slope = -Ea/R

  • y-intercept = ln A

  • A larger activation energy gives a steeper line

Examiner Tips and Tricks

Calculations involving the Arrhenius equation are not assessed on the AP Exam. You do need the qualitative relationships: a higher activation energy gives a smaller k, and a higher temperature gives a larger k because a greater fraction of collisions have energy equal to or greater than Ea. Raising the temperature does not change Ea itself

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Build on this topic

Oluwapelumi Kolawole

Author: Oluwapelumi Kolawole

Expertise: Chemistry Content Creator

Oluwapelumi is a Pharmacist with over 15000+ hours of AP , IB, IGCSE, GCSE and A-Level chemistry tutoring experience. His love for chemistry education has seen him work with various Edtech platforms and schools across the world. He’s able to bring his communication skills as a healthcare professional in breaking down seemingly complex chemistry concepts into easily understood concepts for students.

Stewart Hird

Reviewer: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.