Coupled Reactions (College Board AP® Chemistry): Study Guide

Alexandra Brennan

Written by: Alexandra Brennan

Reviewed by: Stewart Hird

Updated on

Making thermodynamically unfavorable processes occur

  • A thermodynamically unfavorable reaction is one that does not occur spontaneously

    • It occurs only while an external source keeps supplying energy; this is not the same as supplying the activation energy to start a reaction

    • It has a positive ΔG° value

  • A thermodynamically unfavorable process can be made to occur by:

    • Applying external energy sources

    • Coupling it with a thermodynamically favorable reaction that shares an intermediate 

  • Examples of applying external energy include:

    • Electrical energy being used to drive an electrolytic cell or charge a battery

    • Light driving the overall conversion of carbon dioxide to glucose in photosynthesis 

Coupling reactions

  • A desired product can be formed by coupling the thermodynamically unfavorable reaction that produces it to a favorable reaction

    • The two reactions share a common intermediate

  • The sum of the two reactions is a reaction with a negative overall ΔG°

Coupling: decomposition of copper(I) sulfide

  • For example, the decomposition of copper(I) sulfide to produce copper as the desired product and sulfur is thermodynamically unfavorable 

Cu2S (s) ⇌ 2Cu (s) + S (s) ΔG° = +85.1 kJ mol−1 K < 1

  • ΔG° is positive, so K < 1 and the decomposition is not thermodynamically favored: on its own, very little copper forms

  • This reaction can be coupled to a thermodynamically favorable reaction such as the reaction between sulfur and oxygen to give sulfur dioxide

S (s) + O2 (g) ⇌ SO2 (g) ΔG° = −301.4 kJ mol−1 K > 1

  • At equilibrium, the equilibrium constant is greater than 1 so there will be more products than reactants 

  • Coupling these two reactions, which share the common intermediate sulfur, allows a significant amount of copper to form

  • Even if only a small amount, sulfur will still be produced in reaction 1 when copper(I) sulfide decomposes

    • This will then be used up in reaction 2 by reacting with oxygen to produce sulfur dioxide 

  • Adding the two reactions cancels the sulfur, and the overall reaction has a negative ΔG°, so copper forms

  • The thermodynamically favorable second reaction is driving the thermodynamically unfavorable reaction 

  • Adding the two reactions together, the sulfur will cancel out to give:

Cu2S (s) + O2 (g) ⇌ 2Cu (s) + SO2 (g)

  • Adding the two ΔG°values together:

    • +85.1 + (−301.4) = −216.3 kJ mol−1

    • The negative value shows that the overall reaction is thermodynamically favorable

    • It will have an equilibrium constant of above 1

    • Copper will be produced

Coupling: conversion of ATP to ADP

  • Coupling reactions are also used in the conversion of ATP to ADP in the body, which helps drive protein synthesis

    • Amino acids alanine and glycine will produce alanylglycine (a dipeptide) and water: 

alanine + glycine ⇌ alanylglycine + H2O ΔG° = +31 kJ mol−1

  • This is thermodynamically unfavorable due to the positive ΔG° 

  • The hydrolysis of ATP is thermodynamically favorable:

ATP + H2O ⇌ ADP + Pi ΔG° = −33 kJ mol−1

  • The reactions are coupled

  • The water cancels out to give:

alanine + glycine + ATP ⇌ alanylglycine + ADP + Pi

  • Adding the two ΔG° values together gives an overall ΔG° = −2 kJ mol−1

  • The reaction is now thermodynamically favored

Worked Example

Calculate ΔG° for the following reaction: 

Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)

  • Fe2O3 (s) → 2Fe (s) + 1.5O2 (g) (ΔG° = +742.2 kJ mol−1)

  • CO (g) + 0.5O2 (g) → CO2 (g) (ΔG° = −257.2 kJ mol−1)

Answer:

  • The common intermediate is oxygen 

  • To deduce the overall equation, the second equation needs multiplying by three as does the value of ΔG°

    • −257.2 × 3 = −771.6 kJ mol−1

  • ΔG° for the reaction = +742.2 + (−771.6) = −29.4 kJ mol−1

Examiner Tips and Tricks

When you explain coupling:

  • Name the common intermediate and add the ΔG° values

  • The overall ΔG° must be negative

For an electrolytic cell or charging a battery, say that the external source supplies energy continuously. The reaction itself stays thermodynamically unfavored, and the energy is not just there to overcome the activation energy

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Alexandra Brennan

Author: Alexandra Brennan

Expertise: Chemistry Content Creator / Senior Marketing Executive

Alex studied Biochemistry at Newcastle University before embarking upon a career in teaching. With nearly 10 years of teaching experience, Alex has had several roles including Chemistry/Science Teacher, Head of Science and Examiner for AQA and Edexcel. Alex’s passion for creating engaging content that enables students to succeed in exams drove her to pursue a career outside of the classroom at SME.

Stewart Hird

Reviewer: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.