Coupled Reactions (College Board AP® Chemistry): Study Guide
Making thermodynamically unfavorable processes occur
A thermodynamically unfavorable reaction is one that does not occur spontaneously
It occurs only while an external source keeps supplying energy; this is not the same as supplying the activation energy to start a reaction
It has a positive ΔG° value
A thermodynamically unfavorable process can be made to occur by:
Applying external energy sources
Coupling it with a thermodynamically favorable reaction that shares an intermediate
Examples of applying external energy include:
Electrical energy being used to drive an electrolytic cell or charge a battery
Light driving the overall conversion of carbon dioxide to glucose in photosynthesis
Coupling reactions
A desired product can be formed by coupling the thermodynamically unfavorable reaction that produces it to a favorable reaction
The two reactions share a common intermediate
The sum of the two reactions is a reaction with a negative overall ΔG°
Coupling: decomposition of copper(I) sulfide
For example, the decomposition of copper(I) sulfide to produce copper as the desired product and sulfur is thermodynamically unfavorable
Cu2S (s) ⇌ 2Cu (s) + S (s) ΔG° = +85.1 kJ mol−1 K < 1
ΔG° is positive, so K < 1 and the decomposition is not thermodynamically favored: on its own, very little copper forms
This reaction can be coupled to a thermodynamically favorable reaction such as the reaction between sulfur and oxygen to give sulfur dioxide
S (s) + O2 (g) ⇌ SO2 (g) ΔG° = −301.4 kJ mol−1 K > 1
At equilibrium, the equilibrium constant is greater than 1 so there will be more products than reactants
Coupling these two reactions, which share the common intermediate sulfur, allows a significant amount of copper to form
Even if only a small amount, sulfur will still be produced in reaction 1 when copper(I) sulfide decomposes
This will then be used up in reaction 2 by reacting with oxygen to produce sulfur dioxide
Adding the two reactions cancels the sulfur, and the overall reaction has a negative ΔG°, so copper forms
The thermodynamically favorable second reaction is driving the thermodynamically unfavorable reaction
Adding the two reactions together, the sulfur will cancel out to give:
Cu2S (s) + O2 (g) 2Cu (s) + SO2 (g)
Adding the two ΔG°values together:
+85.1 + (−301.4) = −216.3 kJ mol−1
The negative value shows that the overall reaction is thermodynamically favorable
It will have an equilibrium constant of above 1
Copper will be produced
Coupling: conversion of ATP to ADP
Coupling reactions are also used in the conversion of ATP to ADP in the body, which helps drive protein synthesis
Amino acids alanine and glycine will produce alanylglycine (a dipeptide) and water:
alanine + glycine ⇌ alanylglycine + H2O ΔG° = +31 kJ mol−1
This is thermodynamically unfavorable due to the positive ΔG°
The hydrolysis of ATP is thermodynamically favorable:
ATP + H2O ⇌ ADP + Pi ΔG° = −33 kJ mol−1
The reactions are coupled
The water cancels out to give:
alanine + glycine + ATP alanylglycine + ADP + Pi
Adding the two ΔG° values together gives an overall ΔG° = −2 kJ mol−1
The reaction is now thermodynamically favored
Worked Example
Calculate ΔG° for the following reaction:
Fe2O3 (s) + 3CO (g) → 2Fe (s) + 3CO2 (g)
Fe2O3 (s) → 2Fe (s) + 1.5O2 (g) (ΔG° = +742.2 kJ mol−1)
CO (g) + 0.5O2 (g) → CO2 (g) (ΔG° = −257.2 kJ mol−1)
Answer:
The common intermediate is oxygen
To deduce the overall equation, the second equation needs multiplying by three as does the value of ΔG°
−257.2 × 3 = −771.6 kJ mol−1
ΔG° for the reaction = +742.2 + (−771.6) = −29.4 kJ mol−1
Examiner Tips and Tricks
When you explain coupling:
Name the common intermediate and add the ΔG° values
The overall ΔG° must be negative
For an electrolytic cell or charging a battery, say that the external source supplies energy continuously. The reaction itself stays thermodynamically unfavored, and the energy is not just there to overcome the activation energy
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